Answer: No
Explanation:
According to factor theorem, if f(x)=0 then x is a factor of the given function or equation.
As x-1 is a factor
We equate x-1=0
x=1
Substituting in x^5-1, we have 1^5-1 =1-1=0.
Hence, it's a factor.
When coming to x^5+1, it would become 1^5+1=1+1=2
So x-1 isn't a factor of x^5+1.
1/y = -3x /2 + 3
mulytiply each term by 2y:-
2 = -3xy + 6y
y = 2 / -3( (x - 2)
y = -0.667 (-2 + x)
You can find counterexamples to disprove this claim. We have positive integers that are perfect square numbers; when we take the square root of those numbers, we get an integer.
For example, the square root of 1 is 1, which is an integer. So if y = 1, then the denominator becomes an integer and thus we get a quotient of two integers (since x is also defined to be an integer), the definition of a rational number.
Example: x = 2, y = 1 ends up with
which is rational. This goes against the claim that
is always irrational for positive integers x and y.
Any integer y that is a perfect square will work to disprove this claim, e.g. y = 1, y = 4, y= 9, y = 16. So it is not always irrational.
Answer:
20
Step-by-step explanation:
you would take 8 times 2.5 to figure that out