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Anna11 [10]
3 years ago
11

Find the average rate of change between f(-4) and f(-1) in the function f(x)=x^2+2x-8

Mathematics
1 answer:
wel3 years ago
7 0
I got (x+4) (x-2)
I feel like its wrong. Sorry i tried
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4x - 5y = 15 solve for y​
Wewaii [24]

Answer:

y=-\frac{15-4x}{5}

Step-by-step explanation:

4x-5y=15

Subtract 4x from both sides:

4x-5y-4x=15-4x

-5y=15-4x

Divide both sides by -5:

\frac{-5y}{-5}=\frac{15-4x}{-5}

y=-\frac{15-4x}{5}

7 0
2 years ago
HELP ASAP!!!!! WILL GIVE 20 POINTS AND BRAINLIEST!!!!!
Gala2k [10]

Answer:

C.

Step-by-step explanation:

4 0
3 years ago
In a popular online role playing game, players can create detailed designs for their character's "costumes," or appearance. Lata
Artist 52 [7]

Answer:

52/79

Step-by-step explanation:

One costume = 156 (This is our numerator.)

All visitors = 156 + 58 + 23 = 237 (This is our denominator.)

156/237

Find the GCF to simplify (sneak peek it's 3)

156/3 = 52

237/3 = 79

52/79 (tada!)

4 0
2 years ago
A research group wants to know if the online platform to play Settlers of Catan is being accessed more after the stay at home or
Gre4nikov [31]

Answer:

a) The P-value is 0.

At a significance level of 0.05, there is enough evidence to support the claim that the online platform was accessed significantly more so than before the stay at home order.

b) Effect size d = 0.77

Medium.

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that the online platform was accessed significantly more so than before the stay at home order.

Then, the null and alternative hypothesis are:

H_0: \mu=1000\\\\H_a:\mu> 1000

The significance level is 0.05.

The sample has a size n=108000.

The sample mean is M=1378.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=489.

The estimated standard error of the mean is computed using the formula:

s_M=\dfrac{s}{\sqrt{n}}=\dfrac{489}{\sqrt{108000}}=1.488

Then, we can calculate the t-statistic as:

t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{1378-1000}{1.488}=\dfrac{378}{1.488}=254.036

The degrees of freedom for this sample size are:

df=n-1=108000-1=107999

This test is a right-tailed test, with 107999 degrees of freedom and t=254.036, so the P-value for this test is calculated as (using a t-table):

\text{P-value}=P(t>254.036)=0

As the P-value (0) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

At a significance level of 0.05, there is enough evidence to support the claim that the online platform was accessed significantly more so than before the stay at home order.

The effect size can be estimated with the Cohen's d.

This can be calculated as:

d=\dfrac{M-\mu}{\sigma}=\dfrac{1378-1000}{489}=\dfrac{378}{489}=0.77

The values of Cohen's d between 0.2 and 0.8 are considered "Medium", so in this case, the effect size d=0.77 is medium.

5 0
3 years ago
What is 64 minutes (1 hour and 4 minutes) as mixed number? I'm pretty sure its something like this:
Trava [24]

Answer: 1  4/60

Step-by-step explanation

64 is greater then 60 . 60 = 1 hour so  64 minutes = 1 whole 4 over 60

3 0
2 years ago
Read 2 more answers
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