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Klio2033 [76]
3 years ago
5

-9 = 4 - (2x +3)How would you solve this equation?​

Mathematics
2 answers:
Leto [7]3 years ago
6 0

Answer:

Step-by-step explanation:

Here you go mate

Use PEMDAS

Parenthesis,Exponent,Multiplication,Division,Addition,Subtraction

Step 1

-9 =4-(2x+3)  Equation/Question

Step 2

-9 =4-(2x+3)  Remove parenthesis

-9=-2x+1

Step 3

-9=-2x+1  Subtract 1

-2x=-10

Step 4

-2x=-10  Divide by 2

answer

x=5

Hope this helps

arlik [135]3 years ago
3 0

Answer:

x = 5

Step-by-step explanation:

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Because of safety considerations, in May 2003 the Federal Aviation Administration (FAA) changed its guidelines for how small com
Ymorist [56]

Answer:

a) 183-1.984\frac{20}{\sqrt{100}}=179.032    

183+1.984\frac{20}{\sqrt{100}}=186.968    

So on this case the 95% confidence interval would be given by (179.032;186.968)    

b) 190-1.984\frac{23}{\sqrt{100}}=185.437    

190+1.984\frac{23}{\sqrt{100}}=194.563    

So on this case the 95% confidence interval would be given by (185.437;194.563)    

c) For Summer the confidence interval was (179.032;186.968) and as we can see our upper limit is <190 so then we can conclude that they are below the specification of 190 at 5% of significance

For Winter the confidence interval was (185.437;194.563) and again the upper limit is <190 so then we can conclude that they are below the specification of 195 at 5% of significance

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

Part a : Summer

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=100-1=99

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,99)".And we see that t_{\alpha/2}=1.984

Now we have everything in order to replace into formula (1):

183-1.984\frac{20}{\sqrt{100}}=179.032    

183+1.984\frac{20}{\sqrt{100}}=186.968    

So on this case the 95% confidence interval would be given by (179.032;186.968)    

Part b: Winter

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=100-1=99

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,99)".And we see that t_{\alpha/2}=1.984

Now we have everything in order to replace into formula (1):

190-1.984\frac{23}{\sqrt{100}}=185.437    

190+1.984\frac{23}{\sqrt{100}}=194.563    

So on this case the 95% confidence interval would be given by (185.437;194.563)    

Part c

For Summer the confidence interval was (179.032;186.968) and as we can see our upper limit is <190 so then we can conclude that they are below the specification of 190 at 5% of significance

For Winter the confidence interval was (185.437;194.563) and again the upper limit is <190 so then we can conclude that they are below the specification of 195 at 5% of significance

5 0
3 years ago
Write an expression that is equivalent to 3/4(5z+16).
Sphinxa [80]
Answer: 3.75z+12
For an equivalent expression, lets simplify the equation.

3/4(5z+16)
multiply both '5z' and '16' by 3/4
3.75z+12
3 0
3 years ago
Read 2 more answers
Y/5=X<br> Solve for Y.<br><br><br> I NEED HELP ON THIS.
Luden [163]

y/5 = x

multiply by 5 on each sides

y = 5x


There you go! I really hope this helped, if there's anything just let me know! :)

8 0
3 years ago
Read 2 more answers
A snake slithers 2/9 miles in 4/5 hours what is its speed in miles per hour
Mamont248 [21]

Answer:

5/18

Step-by-step explanation:

speed = distance / time

s = (2/9 miles) / (4/5 hours)

To divide by a fraction, multiply by the reciprocal:

s = (2/9) × (5/4)

s = 10/36

s = 5/18

So the snake's speed is 5/18 miles per hour.

3 0
3 years ago
I need this done in 10mins
astra-53 [7]

Answer:

Socko gained 3/5 kg from month 1 to month 2.

Step-by-step explanation:

Socko mass was 3/10 kg in month 1 and 9/10 kg in month 2.

The amount of mass he gained is k.

3/10 + k = 9/10

Subtract 3/10 from both sides.

k = 6/10

Reduce the fraction.

k = 3/5

Answer: Socko gained 3/5 kg from month 1 to month 2.

3 0
3 years ago
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