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hram777 [196]
2 years ago
8

Is 10mm/1cm a converstion factor? Explain

Mathematics
2 answers:
EastWind [94]2 years ago
8 0
Multiple by 10 and the answer will be 10

The answer is 10 because all you are doing is 10x1 = 10


Solution: 10
Alchen [17]2 years ago
7 0

Answer:

Multiply by 10

Step-by-step explanation:

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PLZ HEEEEEEEELPPPPPPPP!!!!!!!!!
Elena L [17]
Y= ∛(-x) - 3
for x = -8 → y = ∛-(-8) - 3 ↔ y = 2-3 ↔y = -1
for x= 8 → y= ∛(-8) - 3 ↔ y = -2 -3 ↔ y = -5
Then  - 5≤ y≤ - 1
hence the range of y is {y|-5≤y≤-1}
5 0
3 years ago
2y-3[3-4(y-5)+2(1-3y)]
soldi70 [24.7K]

Answer:

- 75 - 32y

Step-by-step explanation:

2y-3[3-4(y-5)+2(1-3y)]

= 2y - 3(3 - 4y + 20 + 2 - 6y)

= 2y - 3(25 - 10y)

= 2y - 75 - 30y

= - 75 - 32y

Brainliest???

4 0
3 years ago
Read 2 more answers
Total area of two room <br> Help due soon (no link)
AlladinOne [14]
The answer is B, 2136

Explanation:
48-28 = 20. Now 20 times 20 equals 400, now remember that number.
Now 28 times 62 equals 1,736.
Now back to 400.
400+1736 equals 2,136.

Hope I helped you, please tell me if I am correct or not.

Enjoy your day!
:)
4 0
3 years ago
Joni has a circular garden with a diameter of 14 1/2 feet if she uses 2 teaspoons of fertilizer for every 25 square feet of gard
alina1380 [7]

Answer:

13.20 teaspoon of fertiliser needed for entire garden.

Step-by-step explanation:

Diameter of the garden = 14.50 ft

Radius of the garden = 7.25 ft

Area

[tex]A=\pi r^2[/text]

[tex]A=\pi \times 7.25 \times 7.25[/text]

[tex]\pi=3.14[/text]

[tex]A=\pi \times 7.25 \times 7.25[/text]

[tex]A=3.14 \times 7.25 \times 7.25[/text]

Hence

[tex]A=165.046[/text]

Area is 165.046 Sq Ft

For 25 sq ft of fields the fertiliser needed = 2 tea spoon

For 1 sq ft of fields the fertiliser needed =

[tex]\frac{2}{25}[/text] tea spoon

For 165.046 sq ft of fields the fertiliser needed =

[tex]\frac{2 \times 165.046 }{25}[/text] tea spoon

For 165.046 sq ft of fields the fertiliser needed = 13.20 tea spoon

6 0
3 years ago
Consider the following. y = x2 y = 20 − x Maple Generated Plot (a) Find the area of the region by integrating with respect to x.
Hunter-Best [27]

Answer:

  area = 121.5

Step-by-step explanation:

See below for a plot and the integral. We assume you are interested in the entire bounded region.

__

  \displaystyle\text{area}=\int_{-5}^4{(20-x-x^2)}\,dx=\left.20x-\dfrac{x^2}{2}-\dfrac{x^3}{3}\right|_{-5}^4\\\\=20(4-(-5))-\dfrac{4^2-(-5)^2}{2}-\dfrac{4^3-(-5)^3}{3}\\\\=180+\dfrac{9}{2}-63=121.5

7 0
3 years ago
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