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klasskru [66]
2 years ago
10

1, I cannot fail this if I do I have a F in math!! Please make sure u know it’s correct I can’t do it alone.

Mathematics
1 answer:
Anton [14]2 years ago
3 0

Answer:One way of knowing the correct answers, we substitute the ordered pairs to the function and see whether it would make the function true.

3x – 4y = 21

A. (−3, 3)

3(-3) – 4(3) = 21

-21 = 21 ---------------> not equal

B. (−1, −6)

3(-1) – 4(-6) = 21

21 = 21 ---------------> equal

C. (7, 0)

3(7) – 4(0) = 21

21 = 21 ---------------> equal

D. (11, 3)

3(11) – 4(3) = 21

21 = 21 ---------------> equal

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Suppose the lengths of two sides of a right triangle are represented by 2x and 3 (x + 1), and the longest side is 17 units. Find
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x=4

Step-by-step explanation:

<u>Step 1</u>:-

given the lengths of two sides of a right angle are represented by 2x and 3(x+1) and longest side is 17 units.

AB = 2x and BC = 3(x+1) and longest side AC= 17

by using Pythagoras theorem

AC^2 = AB^2 + BC^2

<u>step 2:-</u>

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(17)^2 = 4x^2 +9(X+1)^2

on simplification, we will use formula

(a + b)^2 = a^2 +2ab+b^2

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finding factors  70 X 52 = 3640

13x^2 +70x-52x-280 = 0

13x^2 -52x+ 70x-280 = 0

Taking common , we get

13x(x-4)+70(x-4)=0

x-4=0 and 13x+70=0

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we can not choose negative value so x value is 4

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<u>verification:-</u>

<u></u>AC^2 = AB^2 + BC^2<u></u>

289 = 4(4)^2+9(4+1)^2

289 = 64 +9(25)

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