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vitfil [10]
3 years ago
12

Jenna jump 156 inches in the long jump competition After High School track meet how many feet did Jenna jump

Mathematics
2 answers:
klio [65]3 years ago
7 0
 13 feet hears how:
156/12=13

divide it 

Hope this helps


melamori03 [73]3 years ago
5 0
Well lets think about it you need to make inches into feet 
if they are telling us the units in inches so if we know i foot has 12 inches we would have to divide 156 by 12
156/12 =13 
so that means she jumped 13 feet in long jump!
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( x - 2 ) ( x + 2 ) ( x bình + 4 ) - ( x bình - 2 ) ( x bình + 3 )
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3 years ago
Which is the equation of an ellipse centered at the origin with foci on x-axis, x-intercepts +7, -7 and y-intercepts +2,
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7 0
3 years ago
A volleyball reaches its maximum of 13 feet, 3 seconds after it is served. What quadratic formula could model the height of the
Katena32 [7]

Answer:

H=-(t-3)^2+13

Step-by-step explanation:

The path covered by the volleyball will be a downward parabola with the vertex being the highest point of the ball.

A general form of a downward parabola is given as:

y=-a(x-h)^2+k

Where (h,k) is the vertex of the parabola and 'a' is a constant.

Now, let 'h' be the vertical height and 't' be the time taken.

So, the equation would be of the form:

H=-a(t-h)^2+k

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h = 2 seconds, k = 13 feet.

H=-a(t-3)^2+13

Now, taking a = 1. So, the formula that can be used is:

H=-(t-3)^2+13

7 0
3 years ago
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