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Answer:
( x - 2 ) ( x + 2 ) ( x² + 4 ) - ( x² - 2 ) ( x² + 3 )
(x²– 4) (x²+4) – (x⁴ + x² – 6)
( x⁴ – 16 ) – ( x⁴ + x² – 6 )
( x⁴ – 16 ) + ( – x⁴ – x² + 6 )
– x² – 10
I hope I helped you^_^
We know that
<span>foci on x-axis-------> is a ellipse with horizontal major axis
the equation is
(x</span>²/a²)+(y²/b²)=1
major axis is th<span>e </span>x<span>-axis with length </span><span>2<span>a
2a=14--------> a=7
</span></span>minor axis is the y<span>-axis with length </span><span>2<span>b
2b=4-----> b=2
the equation is
</span></span>(x²/a²)+(y²/b²)=1------> (x²/7²)+(y²/2²)=1-----> (x²/49)+(y²/4)=1
the answer is(x²/49)+(y²/4)=1
see the attached figure
Answer:

Step-by-step explanation:
The path covered by the volleyball will be a downward parabola with the vertex being the highest point of the ball.
A general form of a downward parabola is given as:

Where
is the vertex of the parabola and 'a' is a constant.
Now, let 'h' be the vertical height and 't' be the time taken.
So, the equation would be of the form:

Now, as per question:
h = 2 seconds, k = 13 feet.

Now, taking a = 1. So, the formula that can be used is:
