All categories

3 years ago

Help me!!!! Pls ASAP

Mathematics

2 answers:

ehidna [41]3 years ago

8 0

Answer:

- $\frac{1}{2}$

Step-by-step explanation:

To get the slope you have to find the difference in Y and put it over the difference in X. (x2-x1)/(y2-y1). You plug in the points and you get -1/2

lapo4ka [179]3 years ago

4 0

Answer:

-1/2

Step-by-step explanation:

Hope this helps.

You might be interested in

Wat is the slope of the line that passes through the points 3,1) and (-2,5)

den301095 [7]

Hi there!

»»————-　★　————-««

I believe your answer is:

$m=\boxed{-\frac{4}{5}}$

»»————-　★　————-««

Here’s why:

We can use the slope formula to find the slope of the two points given.

⸻⸻⸻⸻

$\boxed{\text{Recall that the slope formula is:}}\\\\\frac{y_2-y_1}{x_2-x_1}\\\\(x_1,y_1), (x_2,y_2)-\text{Points}$

⸻⸻⸻⸻

$\boxed{\text{Finding the Slope:}}\\\\\rightarrow m=\frac{5-1}{-2-3} \\\\\rightarrow m=\frac{4}{-5}\\\\\rightarrow \boxed{m= -\frac{4}{5}}$

⸻⸻⸻⸻

»»————-　★　————-««

Hope this helps you. I apologize if it’s incorrect.

8 0

3 years ago

A particle moves along the x–axis so that at time t its position is given by x(t) = (t+1)(t–3)3. For what values of t is the vel

rosijanka [135]

I'll assume that's an exponent at the end there:

$x(t) = (t+1)(t-3)^3$

The first derivative gives the velocity. The second derivative gives the acceleration; increasing velocity is the same as positive acceleration. So we want to find when the second derivative is positive.

Let's see if we can use $d(uv) = u\, dv + v\, du$ to avoid multiplying this out.

$x'(t) = 3 (t+1)(t-3)^2 + (t-3)^3$

That worked; let's do it again:

$x''(t) = 3( 2(t+1)(t-3) + (t-3)^2) + 3(t - 3)^2$

$x''(t) = 3(t-3) ( 2(t+1) + (t-3) + (t - 3) ) = 3(t-3)(4t-4)=12(t-1)(t-3)$

That's a nice parabola. It's zero or negative for $1 \le t \le 3$ so positive everywhere else:

Answer: Increasing velocity when t < 1 or t > 3

4 0

3 years ago

The endpoints of the segment AB are A(-2,4) and B(4,0). Find the endpoints of the image after the segment is reflected over the

serious [3.7K]

Answer:

A' ( 2, 4) and B' ( -4, 0)

Step-by-step explanation:

A ( -2, 4) and B( 4,0) reflected over the y-axis

A' ( 2, 4) and B' ( -4, 0)

the y-coordinate do not change and the x is opposite sign

(x,y) reflected over y-axis (-x, y)

3 0

3 years ago

A tailor cuts 2 3/4 yards from a roll of fabric to make one curtain.

Otrada [13]

Answer:

You know, I really don’t like the 312 notation, I think it’s a lot more confusing than writing 3.5 or even 72. I’ll use the latter here, to make the math easier.

Okay, Erica started with 72 yards of fabric. Then, she uses 2/3 of that. But how much is 23 of 72? All you have to do is multiply!

72⋅23=146=73

Alright, she used 73 yards of fabric in the curtain, if you take that out of the total how much will be left?

72−73=21−146=76

Here it is, she will have 76 yards of fabric left. If you want the answer in that notation, it is 116.

You know, I really don’t like the 312 notation, I think it’s a lot more confusing than writing 3.5 or even 72. I’ll use the latter here, to make the math easier.

Okay, Erica started with 72 yards of fabric. Then, she uses 2/3 of that. But how much is 23 of 72? All you have to do is multiply!

72⋅23=146=73

Alright, she used 73 yards of fabric in the curtain, if you take that out of the total how much will be left?

72−73=21−146=76

Here it is, she will have 76 yards of fabric left. If you want the answer in that notation, it is 116.

7 0

3 years ago

A jet travels from chicago to kansas city at a speed of 440 knots. If it takes a plane 3 hr longer to fly from kansas city to ch

steposvetlana [31]

d = distance between the two cities

v₁ = average speed while going from chicago to kansas city = 440 knots

t₁ = time taken to travel distance going from chicago to kansas city

time taken to travel distance going from chicago to kansas city is given as

t₁ = d/v₁

t₁ = d/440 eq-1

v₂ = average speed while going from kansas city to chicago = 110 knots

t₂ = time taken to travel distance going from kansas city to chicago

time taken to travel distance going from kansas city to chicago is given as

t₂ = d/v₂

t₂ = d/110 eq-2

Given that :

t₂ = t₁ + 3

using eq-1 and eq-2

(d/110) = (d/440) + 3

d = 440

7 0

4 years ago