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svetoff [14.1K]
3 years ago
9

Sort the processes based on the type of energy transfer they involve. condensation freezing deposition sublimation evaporation m

elting thermal energy added thermal energy removed
Physics
1 answer:
Eduardwww [97]3 years ago
6 0

Answer:

condensation - thermal energy removed

freezing -thermal energy removed

deposition - thermal energy removed

sublimation - thermal energy added

evaporation - thermal energy added

melting - thermal energy added

Explanation:

Thermal energy is heat energy. Processes in which heat is added involve the addition of thermal energy while processes in which heat energy is removed involves removal of thermal energy.

Condensation involves a change from gas to liquid, freezing involves a change from liquid to solid while deposition involves the settling of mobile particles at a place. All these processes involve a decrease in energy of particles.

On the other hand, sublimation is a direct change from solid to gas, melting involves a change from solid to liquid while evaporation involves a change from liquid to gas. All these processes occur when energy is added to the particles in a system.

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A 20 g ball of clay traveling east at 4.5 m/s collides with a 45 g ball of clay traveling north at 2.0 m/s. You may want to revi
german

Answer:

The ball travels with a speed of 1.96 m/s in a North East direction

Explanation:

Based on the law of conservation of linear momentum, we have that

m_{1}v_{1}+m_{2}v_{2}=(m_{1}+m_{2})v

Since this problem involves motion in both the x and y coordinates, we will solve it in the separate coordinates, and then find the resultant as our answer.

Momentum in the x- direction

in the x direction, v_{2}= 0. this makes m_{2}v_{2}=0

hence we have

20\times4.5=65v_{x}

v_{x}=1.385m/s

Momentum in the y- direction

in the y direction, v_{1}= 0. this makes m_{1}v_{1}=0

hence we have

45\times2.0=65v_{y}

v_{y}=1.385m/s

The resultant of the two vectors can be found using Pythagoras' theorem

v=\sqrt{1.385^{2}+1.385^{2}} =1.959

The direction of the resultant vector is found as

Tan^{-1}(\frac{1.385}{1.385})=45degrees

Hence the ball moves with a velocity of 1.96m/s in a North East direction

7 0
3 years ago
A car is traveling at 100 km/h when the driver sees an accident 80 m ahead and slams on the brakes. what minimum constant decele
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S is the distance covered after a time t
v_f is the velocity at time t
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The accident is 80 m ahead of the car, so the minimum deceleration required to avoid the accident is the value of a such that S=80 m and v_f=0 (the car should stop exactly at S=80 m to avoid the accident). Using these data, we can solve  the equation (1) to find a:
a=- \frac{v_i^2}{2 S}= -\frac{(27.8 m/s)^2}{2 \cdot 80 m} =-4.83 m/s^2
And the negative sign means it is a deceleration.

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4 years ago
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