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podryga [215]
3 years ago
14

To do work,the force must be applied over a

Physics
2 answers:
pychu [463]3 years ago
6 0
Are there options for this question?
KATRIN_1 [288]3 years ago
6 0
The force is applied over a distance
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Usually, when the temperature is increased, what will happen to the rate of dissolving? A) It will stop. B) It will increase. C)
Montano1993 [528]

C) it will decrease

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3 years ago
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Suppose that the collector is held at a small negative voltage with respect to the grid. Will the accelerated electrons reach th
Leona [35]

Answer:

B) Yes, but only those electrons with energy greater than the potential difference established between the grid and the collector will reach the collector.

Explanation:

In the case when the collector would held at a negative voltage i.e. small with regard to grid So yes the accelerated electrons would be reach to the collecting plate as the kinetic energy would be more than the potential energy that because of negative potential

so according to the given situation, the option b is correct

And, the rest of the options are wrong

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3 years ago
Consider the following distribution of objects: a 5.00-kg object with its center of gravity at (0, 0) m, a 3.00-kg object at (0,
Minchanka [31]

Answer:

(-1.5,-1.5)m

Explanation:

we know that:

X_{cm} = \frac{m_1x_1+m_2x_2....m_nX_n}{m_1+m_2...m_n}

where X_{cm} is the location of the center of gravity in the axis x, m_i is the mass of the object i and x_i the first coordinate of center of gravity of object i.

so:

0 = \frac{(5kg)(0)+(3kg)(0)+(4kg)(3)+(8kg)x_4}{5kg+3kg+4kg+8kg}

Where x_4 is the first coordinate of the center of gravity for the fourth object.

Therefore, solving for x_4, we get:

x_4 = -1.5m

At the same way:

Y_{cm} = \frac{m_1y_1+m_2y_2....m_ny_n}{m_1+m_2...m_n}

where Y_{cm} is the location of the center of gravity in the axis y, m_i is the mass of the object i and y_i the second coordinate of center of gravity of object i. replacing values we get:

Y_{cm} = \frac{(5kg)(0)+(3kg)(4)+(4kg)(0)+(8kg)y_4}{5+3+4+8}

Where y_4 is the second coordinate of the center of gravity for the fourth object.

solving for y_4:

y_4 = -1.5m

It means that the object of mass 8kg have to be placed in the  

coordinates (-1.5,-1.5) m.

8 0
3 years ago
With a quarter-turn flick of the wrist, a student sets the frisbee rotating at 570 rpm . what is the magnitude of the torque, as
Sunny_sXe [5.5K]
Torque: \tau = \overrightarrow r \times \overrightarrow F = rFsin\theta = I\alpha

 
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What can be defined as the rate at which velocity changes
taurus [48]

Answer:

acceleration

Explanation:

The rate at which velocity changes is the definition of the physical quantity called acceleration, and it is given by the formula: a=\frac{v_f-v_i}{\Delta t}

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