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3 years ago

Need help with math pls help me I will mark brainiest

Mathematics

2 answers:

Dmitrij [34]3 years ago

4 0

Answer:

the first one is D, the second one is B i think :)

Step-by-step explanation:

gladu [14]3 years ago

3 0

Answer:

14) D.

15) D.

Step-by-step explanation:

14)

The line has a positive slope, with a y-intercept: (0, 5).

15)

The line has a negative slope, with a y-intercept: (0, -2).

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F(x) = 3x - 5 and g(x) = x + 3, find (1-9)(x).

snow_lady [41]

f(x)= 3x - 5 is x = 5/3

g(x) = x +3 is x = -3

(1-9)(x) is -8x

3 0

3 years ago

I need help or my report card is gonna have a f its coming out tommorow

OverLord2011 [107]

Answer:

Step-by-step explanation:

hope this helps you

8 0

3 years ago

Which line best represents the line of best fit for this scatter plot?

allsm [11]

Answer:

Line D

Step-by-step explanation:

The line of best fit should be the one where majority of the points in the scatterplot lay near it
Line D is the line of best fit for this scatter plot

5 0

2 years ago

Read 2 more answers

Does this set of ordered pairs form a function?

zhenek [66]

Considering that each input is related to only one output, the correct option regarding whether the relation is a function is:

A. yes.

<h3>When does a relation represent a function?</h3>

A relation represents a function when each value of the input is mapped to only one value of the output.

For this problem, we have that:

The input is a number.

The output is an activity.

There are no repeated inputs, hence the relation is a function and option A is correct.

More can be learned about relations and functions at brainly.com/question/12463448

#SPJ1

3 0

2 years ago

Find the distance traveled by a particle with position (x, y as t varies in the given time interval. x = 3?sin2 t, y = 3?cos2 t,

ANTONII [103]

Assuming the particle's position is given by

$\begin{cases}x(t)=3-\sin2t\\y(t)=3-\cos2t\\0\le t\le4\end{cases}$

then the distance traveled over the interval is

$\displaystyle\int_{t=0}^{t=4}\sqrt{\left(\dfrac{\mathrm dx(t)}{\mathrm dt}\right)^2+\left(\dfrac{\mathrm dy(t)}{\mathrm dt}\right)^2}\,\mathrm dt$
$=\displaystyle\int_0^4\sqrt{(-2\cos2t)^2+(2\sin2t)^2}\,\mathrm dt$
$=\displaystyle\int_0^4\sqrt{4\cos^22t+4\sin^22t}\,\mathrm dt$
$=\displaystyle2\int_0^4\mathrm dt$
$=2(4-0)=8$

5 0

3 years ago