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nalin [4]
3 years ago
10

in constructing a box and whisker plot from the data set below at which value would you draw the left and right side of the box

Mathematics
1 answer:
KatRina [158]3 years ago
8 0
A box and whisker plot is a type of statistical graph that shows the median distributions of the data set. The box represents the data median and the medias of the quartiles. The whiskers represents the lines extended from the box to the lowest and the highest data.

Take this data as an example:
<span>3.9,  4.1,  4.2,  4.3,  4.3,  4.4,  4.4,  4.4,  4.4,  4.5,  4.5,  4.6,  4.7,  4.8,  4.9,  5.0,  5.1
</span>First, find the middle value. That would be the median. In this case, that would be 4.4. Let's denote this as Q₂ or Quartile 2. Now, take the group of data set before and after the median. These are:

<span>3.9,  4.1,  4.2,  4.3,  4.3,  4.4,  4.4,  4.4
</span>
and

<span>4.5,  4.5,  4.6,  4.7,  4.8,  4.9,  5.0,  5.1
</span>
The middle of the first data set is Q₁ = 4.3, while the middle of the second set is Q₃ = (4.7+4.8)/2 = 4.75

To construct the box and whisker plot, create line for the lowest value 3,9, Q₁, Q₂, Q₃ and the highest value, 4.4. The left side of the box would be Q₁, while the right side of the box is Q₃. The line in between is the media Q₂. The whiskers are the lines connecting the lowest to Q₁, and Q₃ to the highest on the other side. The resulting box and whisker plot is shown in the attached picture.

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2 years ago
I need help figuring this out asap please
Vera_Pavlovna [14]

Answer:

38.13 ft squared

Step-by-step explanation:

Since it is half of a circle we first find the area of a normal circle then divide by two.

So to find the area of  a circle it is pi times radius squared which in this case it would be 3.14 times 9 = 28.26

Then since it is a half circle we divide by two so

28.26/2 = 14.13

Then to find the area of the triangle we do 4 times 6 which is 24.

now we add the two which is 14.13 + 24 which is

38.13

4 0
3 years ago
A coin is tossed and a single 6 sided number cube is rolled. Find the probability of landing on the heads side of the coin and r
Delicious77 [7]

Answer:

The probability of landing on the heads side of the coin and rolling 3 on the number cube is 0.083.

Step-by-step explanation:

Given:

Coin is tossed and a single 6 sided number cube is rolled.

Let the event of tossing head be 'H' and event of rolling a 3 be 'R3'.

Now, we know that:

Probability of an event 'A' = Favorable outcomes of 'A' ÷ Total possible outcomes

Now, for tossing a coin, the total possible outcomes are head and tail. So, there are 2 possible outcomes.

So, probability of event 'H' is given as:

P(H)=\dfrac{n(H)}{n(S)}\\\\P(H)=\frac{1}{2}=0.5

Similarly, for rolling a 6 sided cube, the possible outcomes are numbers 1 to 6. So, the number of possible outcomes is, n(S)=6

Now, probability of rolling a 3 is given as:

P(R3)=\frac{n(R3)}{n(S)}\\\\P(R3)=\frac{1}{6}

Now, both the events 'H' and 'R3' occur together. So, the combined probability is the product of two individual probabilities as they are independent events. So,

P(H\ and\ R3)=P(H)\times P(R3)\\\\P(H\ and\ R3)=\frac{1}{2}\times \frac{1}{6}\\\\P(H\ and\ R3)=\frac{1}{12}=0.083

Note: Independent events are those events whose intersection is an empty set of events or the outcome of one event doesn't affect the outcome of the other event.

Therefore, the probability of landing on the heads side of the coin and rolling 3 on the number cube is 0.083.

4 0
3 years ago
The weights of 67 randomly selected axles were found to have a variance of 3.85. Construct the 80% confidence interval for the p
VLD [36.1K]

Answer:

3.13

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 67

Variance = 3.85

We have to find 80% confidence interval for the population variance of the weights.

Degree of freedom = 67 - 1 = 66

Level of significance = 0.2

Chi square critical value for lower tail =

\chi^2_{1-\frac{\alpha}{2}}= 51.770

Chi square critical value for upper tail =

\chi^2_{\frac{\alpha}{2}}= 81.085

80% confidence interval:

\dfrac{(n-1)S^2}{\chi^2_{\frac{\alpha}{2}}} < \sigma^2 < \dfrac{(n-1)S^2}{\chi^2_{1-\frac{\alpha}{2}}}

Putting values, we get,

=\dfrac{(67-1)3.85}{81.085} < \sigma^2 < \dfrac{(67-1)3.85}{51.770}\\\\=3.13

Thus, (3.13,4.91) is the required 80% confidence interval for the population variance of the weights.

8 0
3 years ago
John is putting a fence around his garden that is shaped like a half circle and a rectangle. A rectangle has a length of 14 feet
charle [14.2K]

Answer:

Area of the garden = 98 + 19.25 = 117.25 ft²

Step-by-step explanation:

Area of the garden = area of the rectangle + area of the semi-circle

Area of the rectangle = L x B = 14 x 7 = 98 ft²

Area of the semi-circle = 1/2 x πR² = 1/2 x 22/7 x 3.5² = 19.25 ft²

Hence area of the garden = 98 + 19.25 = 117.25 ft²

6 0
3 years ago
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