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2 years ago

Simplify expression (5xy^-6/x^4 y^-2)^2

Mathematics

1 answer:

ipn [44]2 years ago

4 0

Here it is...........................

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Solve the system x + y = 12 and x - y = 2

SOVA2 [1]

Answer:

answer is d

hope it helps

plz mark as brainliest

Step-by-step explanation:

7,5

8,6

9,7

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3 years ago

If f(x) = 6 - 5x, what is f(x)^-1? (check attachment)

SCORPION-xisa [38]

f(x) = 6-5x

y = 6-5x .... replace f(x) with y

x = 6-5y .... swap x and y; solve for y

x+5y = 6

5y = 6-x

y = (6-x)/5

$f^{-1}(x) = \frac{6-x}{5}$ ... replace y with the inverse function notation

<h3>Answer: Choice D.</h3>

6 0

3 years ago

Perform each indicated operation

MissTica

Answer: $\frac{x+6}{x-4}$

Step-by-step explanation:

First you need know some general formuals of factorization such as

$x^3+y^3=(x+y)(x^2-xy+y^2)$ so you have $x^3+64=X^3+4^3=(x+4)(x^2-4x+4^2)$

And, $x^2-y^2=(x-y)(x+y)$ so you have $2x^2-32=2(x^2-16)=2(x^2-4^2)=2(x+4)(x-4)$

If you use them, then you can modify your equations such as

$\frac{x^3+64}{2x^2-32}$ ÷ $\frac{x^2-4x+16}{2x+12}$ = $\frac{(x+4)(x^2-4x+4^2)}{2(x+4)(x-4)}$ ÷ $\frac{x^2-4x+16}{2(x+6)}$ = $\frac{(x+4)(x^2-4x+4^2)}{2(x+4)(x-4)} . \frac{2(x+6)}{{x^2-4x+16}} = \frac{1}{x-4}.\frac{x+6}{1}=\frac{x+6}{x-4}$

4 0

3 years ago

in the first quadrant you start at 11,8 and move 9 units left and 3 units up what point will you end up on

Umnica [9.8K]

Eleven subtract nine is two; eight adding three is eleven (2,11)

8 0

3 years ago

Use these properties to rewrite 7/4 + 1/2 + 5/3 + 1/3 + 1/4 + 1/2 in a way that makes the addition easier. Explain how your chan

Reptile [31]

It makes the addition easier if you combine like terms like the two 1/2s and then make them all have the denominator of 12 (changing the numerators to equal it out)

3 0

3 years ago

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