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bagirrra123 [75]
3 years ago
5

My soccer team has 16 players. I have to choose a starting lineup of a goalie and 10 regular players (the regular players are in

terchangeable). How many different starting lineups can i choose? *the answer is not 4368*
Mathematics
1 answer:
ASHA 777 [7]3 years ago
6 0

Answer:

3003

Step-by-step explanation:

We want to find out how many ways we can choose 10 players among 15 players (since the goalie is not interchangeable)

The number of different lineups you can have can be found by using combination:

^{15}C_{10} = \frac{15!}{(15 - 10)! 10!}\\ \\= \frac{15!}{5! * 10!} \\\\= 3003

There are 3003 different lineups that can be chosen.

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1

Step-by-step explanation:

everything rise 0 power is 1.

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11. When you multiply two decimals less than 1, how does the product compare to the factors?
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Answer:

The product is usually smaller than the two numbers multiplied

Step-by-step explanation:

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3 years ago
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notka56 [123]

Answer:

1)   x=\dfrac12

2)   n = -3 \ \ \textsf{and} \ \ m = -4

3)  see below

4)  A:  0 = 1

Step-by-step explanation:

<u>Question 1</u>

15-0.5(4x-2)+4x=17

\implies 15-2x+1+4x=17

\implies 2x+16=17

\implies 2x=1

\implies x=\dfrac12

<u>Question 2</u>

\textsf{rearrange} \ n=m+1 :

\implies -m=-n+1

\textsf{add equations} \ -m=-n+1 \ \textsf{and} \ m=2n+2:\\

\implies0=n+3

\implies n=-3

\textsf{substitute} \ \ n=-3 \ \ \textsf{into} \ \ m=n-1:

\implies m=-3-1

\implies m=-4

<u>Question 3</u>

subtract the second equation from the first

divide both sides by -4

substitute found value for y into first equation

solve for x

<u>Question 4</u>

3j=k

k=3j+1

\textsf{rearrange} \ 3j=k :

\implies -k=-3j

\textsf{add equations}\  -k=-3j \ \ \textsf{and}\ \ k=3j+1:

\implies 0=1

Solution = A

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What is the quotient of the following rational expression?<br> x^3+3x^2-4x+5/x^2-2
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Answer:

Here:

Step-by-step explanation:

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