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Elanso [62]
2 years ago
12

WHAT IS THE ANSWER PLEASE TELL!

Mathematics
1 answer:
Ganezh [65]2 years ago
8 0
Um ma is tht even right ‍❤️‍‍
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We are given arc KL is 12x+4, arc KJ is 8x-6, and angle E is 99 degrees. What is the actual degree measure of arc KJ? *
Goryan [66]

Answer:

I think its 20x - 2 because when u are given KJ or KL we need the measurement of x

4 0
2 years ago
F ∝ a If F = 48 when a = 3 find, a when F = 32
LenKa [72]

Answer:

2

Step-by-step explanation:

f = a

48 = 3

32 = x

48x= 98

<u>x=2</u>

<h2><u>Mark me as brainiest if i helped you </u></h2>
4 0
2 years ago
Carl is making a garden that is twice as long as it is wide. he wants to cover 271
d1i1m1o1n [39]

x²/2 =271 represents the situation where taking length twice as breadth and area as 271 ft² .

Area of a figure is the amount of space acquired by the figure

Area of a rectangle=Length x  breadth

length=x

breadth=x/2

Area of rectangular lawn=lxb

                                          =x.x/2

But as per question,

Area=271 ft²

⇒x²/2=271 1

⇒x=23.28 ft²

Therefore, x²/2 =271 represents the situation where taking length twice as breadth and area as 271 ft² .Value of x i.e. length is 23.28 ft²

Learn more about area,

brainly.com/question/25292087

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6 0
2 years ago
Two cars leave the same location traveling in opposite directions. One car leaves at 3:00 p.m. traveling at an average rate of 5
sergey [27]
Recall your d = rt,   distance = rate * time

thus \bf \begin{array}{lccclll}&#10;&distance&rate&time(hrs)\\&#10;&-----&-----&-----\\&#10;\textit{first car}&d&55&x\\&#10;\textit{second car}&380-d&75&x+1&#10;\end{array}\\\\&#10;-----------------------------\\\\&#10;&#10;\begin{cases}&#10;\boxed{d}=(55)(x)\\\\&#10;380-d=(75)(x+1)\\&#10;----------\\&#10;380-\left( \boxed{(55)(x)} \right)=(75)(x+1)&#10;\end{cases}

notice, the first car leaves at "x" time, the other leaves on hour later, or x + 1

the first car travels some distance "d", whatever that is, thus
the second car, picks up the slack, or the difference, they're 380 miles
apart, thus the difference is 380-d
8 0
3 years ago
A bag contain 3 black balls and 2 white balls.
Troyanec [42]

Answer:

Step-by-step explanation:

Total number of balls = 3 + 2 = 5

1)

a)

Probability \ of \ taking \ 2 \ black \ ball \ with \ replacement\\\\ = \frac{3C_1}{5C_1} \times \frac{3C_1}{5C_1} =\frac{3}{5} \times \frac{3}{5} = \frac{9}{25}\\\\

b)

Probability \ of \ one \ black \ and \ one\ white \ with \ replacement \\\\= \frac{3C_1}{5C_1} \times \frac{2C_1}{5C_1} = \frac{3}{5} \times \frac{2}{5} = \frac{6}{25}

c)

Probability of at least one black( means BB or BW or WB)

 =\frac{3}{5} \times \frac{3}{5} + \frac{3}{5} \times \frac{2}{5} + \frac{2}{5} \times \frac{3}{5} \\\\= \frac{9}{25} + \frac{6}{25} + \frac{6}{25}\\\\= \frac{21}{25}

d)

Probability of at most one black ( means WW or WB or BW)

=\frac{2}{5} \times \frac{2}{5} + \frac{3}{5} \times \frac{2}{5} \times \frac{2}{5} + \frac{3}{5}\\\\= \frac{4}{25} + \frac{6}{25} + \frac{6}{25}\\\\=\frac{16}{25}

2)

a) Probability both black without replacement

  =\frac{3}{5} \times \frac{2}{4}\\\\=\frac{6}{20}\\\\=\frac{3}{10}

b) Probability  of one black and one white

 =\frac{3}{5} \times \frac{2}{4}\\\\=\frac{6}{20}\\\\=\frac{3}{10}

c) Probability of at least one black ( BB or BW or WB)

 =\frac{3}{5} \times \frac{2}{4} + \frac{3}{5} \times \frac{2}{4} + \frac{2}{5} \times \frac{3}{4}\\\\=\frac{6}{20} + \frac{6}{20} + \frac{6}{20} \\\\=\frac{18}{20} \\\\=\frac{9}{10}

d) Probability of at most one black ( BW or WW or WB)

 =\frac{3}{5} \times \frac{2}{4} + \frac{2}{5} \times \frac{1}{4} + \frac{2}{5} \times \frac{3}{4}\\\\=\frac{6}{20} + \frac{2}{20} + \frac{6}{20} \\\\=\frac{14}{20}\\\\=\frac{7}{10}

6 0
3 years ago
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