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Slav-nsk [51]
3 years ago
11

Simon and Greg shared pencils in the ratio 7:5. If Simon gives away 30 pencils and Greg gets 30 more pencils, they will have the

same number of pencils. How many did each of them have in the beginning?
Mathematics
1 answer:
Nutka1998 [239]3 years ago
8 0
7/5=s/g multiply both sides by g

7g/5=s  multiply both sides by 5/7

g=5s/7

We are then told that:

g+30=s-30  subtract 30 from both sides

g=s-60, and from earlier g=5s/7, and g=g so we can say:

s-60=5s/7  multiply both sides by 7

7s-420=5s  subtract 5s from both sides

2s-420=0  add 420 to both sides

2s=420 divide both sides by 2

s=210, and since g=s-60

g=150

So Simon had 210 pencils and Greg had 150 pencils.

Check..

s:g=210:150=7:5

and

s-30=g+30

210-30=150+30

180=180
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