If it reaches its maximum height a t=3 its velocity must be zero at t=3
dy/dx=0 at t=3
dA/dx=4x+12=24 at t=3 so this does not apply
dB/dx=-4x+12=0 at t=3 and B=13 at t=3 so B applies
dC/dx=-4x-12=-24 at t=3 so this does not apply
dD/dx=-4x-12=-24 at t=3 so this does not apply
dE/dx=-4x-12=-24 at t=3 so this does not apply
So only quadratic B: reaches a maximum height of 13 feet at 3 seconds.
Answer:
1 inch
Step-by-step explanation:
Basically cause both b and c tend to form an equidistant triangle which makes them have the same distance
Answer:
$11.67
Step-by-step explanation:
$43.19÷3.7=11.672972973, which rounds to $11.67.
First, we are going to find the radius of the yaw mark. To do that we are going to use the formula:

where

is the length of the chord

is the middle ordinate
We know from our problem that the tires leave a yaw mark with a 52 foot chord and a middle ornate of 6 feet, so

and

. Lets replace those values in our formula:




Next, to find the minimum speed, we are going to use the formula:

where

is <span>drag factor
</span>

is the radius
We know form our problem that the drag factor is 0.2, so

. We also know from our previous calculation that the radius is

, so

. Lets replace those values in our formula:



mph
We can conclude that Mrs. Beluga's minimum speed before she applied the brakes was
13.34 miles per hour.
Answer:I think it’s 61 minutes
Step-by-step explanation: