Question

HELP!!!! BRAINLIEST!! Jason says that if you multiply each length in a Pythagorean triple by the same factor, you will get another Pythagorean triple. Explain why Jason is correct.

Answer 1

Answer:

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Answer 2

According to Pythagoras theorem,

c²=a²+b²

As we multiply all three numbers by any factor k we get:

(kc)²=(ak)²+(kb)²,

k²C²=k²(a²+b²)

which is right. So pythagorean equality is still working so as Jason said we got another pythagorean triple.

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