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2 years ago

Factor completely: x^3 - x^2 - 6x

Mathematics

1 answer:

PSYCHO15rus [73]2 years ago

4 0

Answer:

$x(x-3)(x+2)$

Step-by-step explanation:

1. Find the GCF (Greatest Common Factor)

$GCF=x$

2. Factor out the GCF and simplify.

$x(x^{2} -x-6)$

3. Factor $x^{2} -x-6.$

Which two numbers add up to -1 and multiply to -6?

-3 and 2

Rewrite the expression using the numbers above.

$(x-3)(x+2)$

4. Done!

$x(x-3)(x+2)$

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How do I graph this

disa [49]

Answer:

ight so you put a dot at -2 and then go up like, go up -2 line until you look across and it says 7 and put a dot there

Step-by-step explanation:

7 0

3 years ago

The number of texts per day by students in a class is normally distributed with a

kobusy [5.1K]

Answer:

1, 2, 6

Step-by-step explanation:

The z score shows by how many standard deviations the raw score is above or below the mean. The z score is given by:

$z=\frac{x-\mu}{\sigma} \\\\where\ x=raw\ score,\mu=mean, \ \sigma=standard\ deviation$

Given that mean (μ) = 130 texts, standard deviation (σ) = 20 texts

1) For x < 90:

$z=\frac{x-\mu}{\sigma} \\\\z=\frac{90-130}{20} =-2$

From the normal distribution table, P(x < 90) = P(z < -2) = 0.0228 = 2.28%

Option 1 is correct

2) For x > 130:

$z=\frac{x-\mu}{\sigma} \\\\z=\frac{130-130}{20} =0$

From the normal distribution table, P(x > 130) = P(z > 0) = 1 - P(z < 0) = 1 - 0.5 = 50%

Option 2 is correct

3) For x > 190:

$z=\frac{x-\mu}{\sigma} \\\\z=\frac{190-130}{20} =3$

From the normal distribution table, P(x > 3) = P(z > 3) = 1 - P(z < 3) = 1 - 0.9987 = 0.0013 = 0.13%

Option 3 is incorrect

4) For x < 130:

$z=\frac{x-\mu}{\sigma} \\\\z=\frac{130-130}{20} =0$

For x > 100:

$z=\frac{x-\mu}{\sigma} \\\\z=\frac{100-130}{20} =-1.5$

From the normal table, P(100 < x < 130) = P(-1.5 < z < 0) = P(z < 0) - P(z < 1.5) = 0.5 - 0.0668 = 0.9332 = 93.32%

Option 4 is incorrect

5) For x = 130:

$z=\frac{x-\mu}{\sigma} \\\\z=\frac{130-130}{20} =0$

Option 5 is incorrect

6) For x = 130:

$z=\frac{x-\mu}{\sigma} \\\\z=\frac{160-130}{20} =1.5$

Since 1.5 is between 1 and 2, option 6 is correct

5 0

2 years ago

How many five-digit codes can be made if the first number cannot be a 0 or a 1 and no numbers can repeat?

Makovka662 [10]

Answer:

24,192.

Step-by-step explanation:

The first number must be one of 2,3,4,5,6,7,8 or 9. That is 8 possibilities.

The number of permutations of the other 4 numbers is 9P4

= 9! / (9-4)!

= 3024

Now we multiply by the 8:

3024 * 8

= 24,192.

6 0

3 years ago

Please answer me QICK. Can the square root also be a decimal number?

Sladkaya [172]

Answer:

yes

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

What is the value of 5^3i^9?

Yakvenalex [24]

Answer:

$\displaystyle 125^i$

Step-by-step explanation:

Extended Information on the Complex Number System

$\displaystyle \sqrt{-1} = i \\ -1 = i^2 \\ -i = i^3 \\ 1 = i^4\:[all\:multiples\:of\:four]$

I am joyous to assist you at any time.

All work is shown above. ↑

4 0

2 years ago