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inessss [21]
3 years ago
6

PLZZZ FASTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTT

Mathematics
1 answer:
Inessa [10]3 years ago
3 0

Answer:

130°

130-67=

63÷3=

21

x=21

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Find the midpoint of the segment with the given endpoints.
Ksju [112]

The mid-point for given endpoints is (4,3)

Step-by-step explanation:

a mid-point is the point on a line segment that divides it into two equal portions.

If (x1,y1) and (x2,y2) are the coordinates of vertices of a line segment, then mid-point is given by:

M = (\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})

given

(x1,y1) = (9,9)

(x2,y2) = (-1,-3)

M = (\frac{9-1}{2}, \frac{9-3}{2})\\\\=(\frac{8}{2}, \frac{6}{2})\\\\=(4,3)

The mid-point for given endpoints is (4,3)

Keywords: Coordinate Geometry, Mid-point

Learn more about coordinate geometry at:

  • brainly.com/question/4639731
  • brainly.com/question/4655616

#LearnwithBrainly

5 0
3 years ago
A 4-column table with 4 rows. The first column has no label with entries C, D, E, total. The second column is labeled A with ent
Dahasolnce [82]

Answer:

0.69

Step-by-step explanation:

Just did it on edge and got it right

8 0
3 years ago
Read 2 more answers
3/4 x 1/8 in simples form
Zielflug [23.3K]

Answer:

3/32

Step-by-step explanation:

To get this answer, multiply the numerators together and the denominators together

3x1=3

4x8=32

3/32

5 0
3 years ago
What is a system of equations for the following situation? A group of 12 people went to see a movie. The cost to go to the movie
Anna11 [10]

First define the variables:

c = amount of children

a = amount of adults

Next create the equations to satisfy the conditions:

1) Total group is 12 people:

c+a=12

2) Total cost is $100 with adults costing $10 and children being $6:

6c+10a=100

6 0
3 years ago
Read 2 more answers
Iv)<br>6x+3y=6xy<br>2x + 4y= 5xy​
Margaret [11]

Answer:

Ok, we have a system of equations:

6*x + 3*y = 6*x*y

2*x + 4*y = 5*x*y

First, we want to isolate one of the variables,

As we have almost the same expression (x*y) in the right side of both equations, we can see the quotient between the two equations:

(6*x + 3*y)/(2*x + 4*y) = 6/5

now we isolate one off the variables:

6*x + 3*y = (6/5)*(2*x + 4*y) =  (12/5)*x + (24/5)*y

x*(6 - 12/5) = y*(24/5  - 3)

x = y*(24/5 - 3)/(6 - 12/5) = 0.5*y

Now we can replace it in the first equation:

6*x + 3*y = 6*x*y

6*(0.5*y) + 3*y = 6*(0.5*y)*y

3*y + 3*y = 3*y^2

3*y^2 - 6*y = 0

Now we can find the solutions of that quadratic equation as:

y = \frac{6 +- \sqrt{(-6)^2 - 4*3*0} }{2*3} = \frac{6 +- 6}{6}

So we have two solutions

y = 0

y = 2.

Suppose that we select the solution y = 0

Then, using one of the equations we can find the value of x:

2*x + 4*0 = 5*x*0

2*x = 0

x = 0

(0, 0) is a solution

if we select the other solution, y = 2.

2*x + 4*2 = 5*x*2

2*x + 8 = 10*x

8 = (10 - 2)*x = 8x

x = 1.

(1, 2) is other solution

8 0
2 years ago
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