Value 14 so it must be 55 or something
The next three terms are: -3, 6, and 15
To get each new term, we simply add 9 to the last term. So we add 9 to -12 to get -3. Then we add 9 to -3 to get 6. Finally we add 9 to 6 to get 15
In other words,
first term = -12
second term = first term+9 = -12+9 = -3
third term = second term + 9 = -3+9 = 6
fourth term = third term + 9 = 6+9 = 15
This process repeats forever though we only need three terms in this case.
So that's why the answer is the three values -3, 6 and 15
Answer:
0.2322 or 23.22 %
Step-by-step explanation:
We have to solve and find the area out of these limits
μ + 0,3 = 210 + 0,3 ⇒ 210,3 and
μ - 0,3 = 210 - 0,3 ⇒ 209.7
z(l) = ( x - 210 ) / (2.8/√84) ⇒ z(l) = - (0.3 * 9,17)/ 2.8
z (l) = - 1.195
We need to interpole from z table
1.19 ⇒ 0.1170
1.20 ⇒ 0.1151
Δ ⇒ 0.01 ⇒ 0.0019
And between our point 1,195 and 1,19 the difference is 0.005
then 0.01 ⇒ 0.0019
0.005 ⇒ ?? (x)
we find x = 0.00095
to get the area for poin z (l) - 1.195 up to final left tail is from z table
0,1170 - 0.00095 = 0.1161
And by symmetry to the right is the same
So 0.1161 * 2 = 0.2322
We find the area out of the above indicated limits the area we were looking for. This is the probability of finding shafts over and below the population mean and 0.3 inches
Step-by-step explanation:
Answer:
20 minutes
Step-by-step explanation:
Remember that
we know that
Hector has 3/4 hour to spend his homework
Convert to minutes
so
1) He wants to spend 1/3 of this time on math homework
To find out the time on math homework, multiply 45 minutes by 1/3
2) He wants to spend 10 minutes of his time on reading homework
3) He wants to spend the remaining time on science homework
The time spend on math homework plus the time spend reading homework, plus the time spend on his science homework must be equal to 45 minutes
Let
x ----> the time spend on his science homework
Solve for x
Answer:
Type in AR, DQ,BS, CP, It's tilted sideways.
Step-by-step explanation:
