we know that
p^2 is the the frequency of hba homozygote
we are given
frequency of hba homozygotes is 0.1
so,
p^2 =frequency of hba homozygotes
we can plug values
and we get
..............Answer
0.08x+(x-200)
(0.08x)(x+-200)
(0.08x)(x)(0.08x)(-200)
= 0.08x^2-16x
Answer:
It's A.
Step-by-step explanation:
5x2 + 60x = 0
5x is the GCF so:
5x(x + 12 ) = 0
5x = 0, x + 12 = 0
x =0, x = -12.