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nikklg [1K]
3 years ago
12

If △PQR ~ △SQT, find the value of x.

Mathematics
2 answers:
Georgia [21]3 years ago
8 0

Answer:

x = 15

Step-by-step explanation:

x+13/9 = 21/x-9

x^2+4x−117=168

x^2+4x−285=0

(x−15)(x+19)=0

x=15

it cannot be a negative number so x cannot be -19

malfutka [58]3 years ago
3 0

Answer:

x = 15 or x = -19

Step-by-step explanation:

ΔPQR similar to ΔSQT

SQ / QP = ST / PR

8 / 8+x+5 = x-9 / 21

8 / 13+x = x-9 / 21

(x+13)(X-9) = 168

x² + 4x - 117 = 168

x² + 4x - 285 = 0

(x - 15) (x + 19) = 0

x = 15 or x = -19

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Answer:

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2 years ago
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The given three numbers are 5,8,24.

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There are many more examples that you can write.

Keep in mind

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2. Difference of rational and irrational is always irrational.

As none of the 5,8,24 is a perfect square , nor addition of any two results in a perfect square, so square root of their addition or subtraction  or multiplication results in an  irrational number.

Similarly ,apart from 8, none of 5,24 is a perfect cube.So if you add or subtract any number from 8 and take their cube root  or square root ,results in an irrational number.

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