5. 6√3
6. x = 10√3 y = 30
7. x = 34 y = 17√3
8. 30
9. SinA = 3/5 CosA = 4/5
10. Tan20 = 9/x
Multiply both sides by x to get it on the other side
x(tan20) = 9
Divide 9 by tan20 to get x.
x = 9/tan20
x = 24.7
To solve this we are going to use the formula for the area of a circle:
where
is tte radius of the circle
We can infer that the bases of our cylinder are circles with 2 in radius, so
. Since we have tow circles, we are going to multiply the area by 2:
We can conclude that the <span>the combined area of the two bases of the cylinder is </span><span>
25.12 in.2</span>
Answer:
$5909.50
Step-by-step explanation:
First, converting R percent to r a decimal
r = R/100 = 3%/100 = 0.03 per year,
then, solving our equation
I = 5575 × 0.03 × 2 = 334.5
I = $ 334.50
The simple interest accumulated
on a principal of $ 5,575.00
at a rate of 3% per year
for 2 years is $ 334.50.
Step-by-step explanation:
Please find the attachment.
We have been given a circle and we are asked to prove that TO is the bisector of angle BTC.
To prove that TO is bisector of angle BTC, we just need to prove that angle BTO is congruent to angle CTO.
We have been given that TB and Tc are tangents to circle O. Since we know that tangents that meet at same point are equal in length.
Since O is the center of our given circle, so OB and OC will be the radii of our given circle.
Since all the points on a circle are equidistant from the center and radius of circle has one one endpoint on the circle and one at the center, so all radii of a circle are congruent.
We also know that a tangent to a circle is perpendicular to the radius drawn to the point of tangency. As OB and OC are radii and TB and TC are tangents of our given circle,
We can see in our triangles TBO and TCO that,
Therefore, by SAS congruence .
So by corresponding parts of congruent triangles are congruent , therefore, TO is the bisector of .
Answer:
Joshua has 2a^2 -6a + 7 more than Maranda.
Step-by-step explanation:
Joshua has 6a^2 -5a + 10 dollars and Maranda has 4a^2 + a + 3 to find out how much more money Joshua has we need to subtract the amount he has by the amount of Maranda's account. Since both expressions are pollynomial we'll have to subtract the numbers wich are multiplying the same power, so we do as follow:
6a^2 - 5a + 10 - (4a^2 + a + 3)
6a^2 - 5a + 10 - 4a^2 -a -3
6a^2 - 4a^2 -5a -a + 10 -3
2a^2 -6a + 7
Joshua has 2a^2 -6a + 7 more than Maranda.