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m_a_m_a [10]
3 years ago
7

Help please. Solve the system of equations using substitution. Show your work in the workspace provided below.

Mathematics
1 answer:
LenKa [72]3 years ago
6 0

Answer:

x=0 y=-11 (0,-11)

Step-by-step explanation:

1. take what y equals (3x-11) and plug it in for y in the second equation

Should look like this: O= 6x-2(3x-11)-22

2. Then distribute O=6x-6x+22-22

3. Then combine like terms O= 0 the 22's cancel out as well as the x's

x= 0

4. plug 0 in for x in the first equation y=3(0)-11

5. y= -11

6. x=0 y=-11 (0,-11)

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Read 2 more answers
For a school fund raising project, Aiden and Jacob collected money in the ratio of 3.5 : 6.8. Jacob collected $115.50 more than
user100 [1]
X - the amount of money collected by Aiden
y - the amount of money collected by Jacob

Aiden and Jacob collected money in the ratio of 3.5 : 6.8.
\frac{x}{y}=\frac{3.5}{6.8} \\
6.8x=3.5y \\
x=\frac{3.5}{6.8}y \\ x=\frac{35}{68}y

Jacob collected $115.50 more than Aiden.
x+115.5=y \\
x=y-115.5 \\ \\
x=x \\
\frac{35}{68}y=y-115.5 \\
\frac{35}{68}y-y=-115.5 \\
\frac{35}{68}y-\frac{68}{68}y=-115.5 \\
-\frac{33}{68}y=-115.5 \\
y=-115.5 \times (-\frac{68}{33}) \\
y=238 \\ \\
x=y-115.5=238-115.5=122.5 \\ \\
x+y=238+122.5=360.5

The total amount of money they collected is $360.50.
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4 years ago
SOMEONE PLEASE HELP ME WITH THIS !!!!!!
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