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bekas [8.4K]
3 years ago
12

Please answer these 2 questions

Mathematics
2 answers:
charle [14.2K]3 years ago
4 0
1. Perpendicular to its radius
2. 0
iren2701 [21]3 years ago
4 0
Yes the first person is right.
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A line passes through the points (2,18) and (8,24). Write a linear function rule in terms of x and y for this line. The linear f
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Step-by-step explanation:

hello : here is an solution

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Point A is located at (2, 6), and D is located at (−4, 10). Find the coordinates of the point that lies halfway between A and D.
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(( \frac{1}{2} (( - 4) - 2) + 2and( \frac{1}{2} (10 - 6)) + 6
the answer is(-1,8)
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How many triangles can be constructed with 3 angles, each measuring 63°?
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a triangle's angles should add up to be 180 degrees. Three angles of 63's sum is 189

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Find a and b if the point p(6,0) and Q(3,2) lie on the graph of ax+ by=12
tiny-mole [99]

to get the equation of any straight line we only need two points off of it, hmmm let's use P and Q here and then let's set the equation in standard form, that is

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(\stackrel{x_1}{6}~,~\stackrel{y_1}{0})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{2}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{2}-\stackrel{y1}{0}}}{\underset{run} {\underset{x_2}{3}-\underset{x_1}{6}}}\implies \cfrac{2}{-3}\implies -\cfrac{2}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{0}=\stackrel{m}{-\cfrac{2}{3}}(x-\stackrel{x_1}{6})

\stackrel{\textit{multiplying both sides by }\stackrel{LCD}{3}}{3(y-0)~~ = ~~3\left( -\cfrac{2}{3}(x-6) \right)}\implies 3y=-2(x-6) \\\\\\ 3y=-2x+12 \implies \stackrel{a}{2} x+\stackrel{b}{3} y=12

5 0
2 years ago
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