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3 years ago

Determine if the two triangles are congruent. If they are, state how you know.

Mathematics

1 answer:

blondinia [14]3 years ago

3 0

All are congruent. Congruent means identical in size or shape. the different markings on the two shapes show that they are congruent. I can’t fully see number 10 so I can’t say it that one is or not

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PLEASE PLEASE PLZZ HELP :(((((

xxMikexx [17]

Answer:

Step-by-step explanation:

Also the first one ends in divided by 1/4

4 0

3 years ago

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The area of the large rectangle is twice the area of the small rectangle. What is the value of x?Two rectangles are shown. The l

kupik [55]

Answer:

B. 8 cm.

Step-by-step explanation:

The area of a rectangle is the length*width.

The area of the larger rectangle is 4*12=48.

The area of the smaller rectangle is 3*x=3x.

If the larger rectangle's area is twice that of the smaller rectangle, then we can say 48=2*3x.

Let's solve for x

48=2*3x

48=6x

x=8

3 0

3 years ago

How do you solve sarah is twice as old as her youngest brother. if the difference between their ages is 15 years. how old is her

marishachu [46]

The youngest brother is 15 years old

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4 years ago

Points P and Q belong to segment AB . If AB = a, AP = 2PQ = 2QB, find the distance: between the midpoints of segments AP and QB

amid [387]

Answer:

$\frac{a}{8}$

Step-by-step explanation:

AB = a

AP = 2PQ = 2QB

AB = AP + PQ + QB

= AP + $\frac{AP}{2}$ + $\frac{AP}{2}$

AB = 2AP

AP = $\frac{a}{2}$ -----(1)

And we know QB = $\frac{AP}{2}$

QB= AP/2 = $\frac{a}{4}$ ---------(2)

Now midpoint of AP = $\frac{a}{2}$ × $\frac{1}{2}$ = $\frac{a}{4}$

and midpoint of QB = $\frac{a}{4}$ × $\frac{1}{2}$ = $\frac{a}{8}$

distance between these midpoints = $\frac{a}{4}$ - $\frac{a}{8}$

= $\frac{a}{8}$

4 0

4 years ago

Read 2 more answers

Find the value of y.

Phoenix [80]

$\boxed{y=6\sqrt{3}}$

<h2>Explanation:</h2>

For a better understanding of the problem I've built up two triangles from the given triangular shape. So these two triangles are similar. Therefore, we can solve this problem by using ratios and corresponding sides in this way:

$\frac{x}{3}=\frac{12}{x} \\ \\ x^2=36 \\ \\ x=\sqrt{36} \\ \\ x=6$

But our goal is to find y. Let's call w the height of the small triangle, then:

$w=\sqrt{6^2-3^2}=3\sqrt{3}$

Applying the concept of ratios again:

$\frac{y}{w}=\frac{x}{3} \\ \\ y=w \left(\frac{x}{3}\right) \\ \\ y=3\sqrt{3}\left(\frac{6}{3}\right) \\ \\ \boxed{y=6\sqrt{3}}$

<h2>Learn more:</h2>

Right triangle: brainly.com/question/10684799

#LearnWithBrainly

4 0

3 years ago