Two shapes that represent the cross-sections
1 answer:
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Answer:
x= -5 + 5, x= -5 - 5
Step-by-step explanation:
Since this quadratic is set to zero, we can use the quadratic formula to solve this.
x^2 + 10x - 2400 = 0
Quadractic formula = x= -b +- /2a
For this equation:
a= 1, b=10, c=-2400
Plug these numbers into the equation and solve.
x= -10 +- )/2(1)
x= -10 +- /2
x= -10 +- /2
x= -10 +- /2
x= -10 +- 5 * 2/2
x= -10 +- 10 / 2
Divide by 2.
x= -5 +- 5
Answer:
x= -5 + 5 or x= -5 - 5
The value of k is
Given:
x-y=k.............(eq i)
2x²+y²-15..............(eq ii)
We would make y the subject formula in eq ii
2x²+y²-15= 0
2x² + y²= 15
y²= 15-2x²
y= ...........(eq iii)
Substitute the value of y into eq i
x-(= k
x- (= k
k=
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