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kondaur [170]
3 years ago
9

What is 8 divided by 8 with a multitude of 53 degree angles

Mathematics
1 answer:
Pachacha [2.7K]3 years ago
3 0

Answer:

1

Step-by-step explanation:

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62 strings of orange lights and 22 strings of yellow lights were used in the house each string of lights has 36 bulbs how many b
Allisa [31]

62 + 22 = 84 total light strings.

36 bulbs/string multiplied by 84 light strings = 3,024 total light bulbs

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Lunch break: In a recent survey of 643 working Americans ages 25-34, the average weekly amount spent on lunch as $43.21 with sta
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Answer:

107%

Step-by-step explanation:

Round up all possible algorithms

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$123.74856 rounded to the nearest cent would be?
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Solve for "X"<br> 4x – 0 = 12<br> hurry
soldier1979 [14.2K]

Step-by-step explanation:

4x-0=12

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3 years ago
An urn contains two black balls and three red balls. If two different balls are successively removed, what is the probability th
lidiya [134]

You can extract two balls of the same colour in two different way: either you pick two black balls or two red balls. Let's write the probabilities of each pick in each case.

Case 1: two black balls

The probability of picking the first black ball is 2/5, because there are two black balls, and 5 balls in total in the urn.

The probability of picking the second black ball is 1/4, because there is one black ball remaining in the urn, and 4 balls in total (we just picked the other black one!)

So, the probability of picking two black balls is

P(\text{two blacks}) = \dfrac{2}{5} \cdot \dfrac{1}{4} = \dfrac{2}{20} = \dfrac{1}{10}

Case 2: two red balls

The probability of picking the first black ball is 3/5, because there are three red balls, and 5 balls in total in the urn.

The probability of picking the second red ball is 2/4=1/2, because there are two red balls remaining in the urn, and 4 balls in total (we just picked the other red one!)

So, the probability of picking two red balls is

P(\text{two reds}) = \dfrac{3}{5} \cdot \dfrac{1}{2} = \dfrac{3}{10}

Finally, the probability of picking two balls of the same colour is

P(\text{same colour}) = P(\text{two blacks})+ P(\text{two reds}) = \dfrac{1}{10} + \dfrac{3}{10} = \dfrac{4}{10} = \dfrac{2}{5}

7 0
3 years ago
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