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antoniya [11.8K]
3 years ago
12

Over the course of the school year, you keep track of how much snow falls on a given day and whether it was a snow day. Your dat

a indicates that of twenty-one days with less than three inches of snow, five were snow days, while of the eight days with more than three inches of snow, six were snow days. If all you know about a day is that it is snowing, what is the probability that it will be a snow day?
Mathematics
1 answer:
Free_Kalibri [48]3 years ago
5 0

Answer:

Probability of the day to be a snow day is 0.34

Step-by-step explanation:

We have the data,

Out of 21 which had less than 3 inches of snow, 5 were snow days.

Out of 8 days which had more than 3 inches of snow, 6 were snow days.

So, we get,

Total number of days = 21 + 8 = 29

Total number of snow days = 5 + 6 = 11

Thus, the probability that the day will be a snow day is \frac{11}{29} i.e. 0.34

Hence, the probability of the day to be a snow day is 0.34.

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I think I got this for the most part just need to be surs
defon

Answer:

a) 37.33 tons

b) 96 tons

c) Week 2

Step-by-step explanation:

a) 40+40+32=112÷3=37.33 tons

b) 32+40+24=96 tons

c) Week 2

6 0
3 years ago
The same couple, what is the probability that if they have three children, two will be boys and one will be a
cricket20 [7]
3/8 would be the correct answer.

8 0
3 years ago
If you roll a dice 100 times how many times would you expect to roll a product that is a multiple of 5
Luden [163]

If you're rolling a single cube, then ...

-- There are 6 possible out comes.
-- One of them (5) is a multiple of 5 .
-- The probability of rolling it is (1/6) = <em>16-2/3 %</em> .

If everything is acting perfectly random, then ion 100 rolls,
you'd expect to succeed 16 or 17 times.


If you're rolling a pair of cubes, then ...

-- There are (6 x 6) = 36 possible outcomes.
-- There are seven ways to get a multiple of 5.
(1+4),  (4+1),  (2+3),  (3+2),  (4+6),  (6+4),  (5+5)
-- The probability of rolling one of those is
                                                             (7/36) = <em>19-4/9 %</em> .

If everything is acting perfectly random, then in 100 rolls,
you'd expect to succeed 19 or 20 times.


3 0
3 years ago
∠A and \angle B∠B are supplementary angles. If m\angle A=(7x+10)^{\circ}∠A=(7x+10) ∘ and m\angle B=(7x-26)^{\circ}∠B=(7x−26) ∘ ,
blsea [12.9K]

Answer:

108 degrees

Step-by-step explanation:

Since angles A and B are supplementary, they both add up to 180. Angle A = 7x+10, and angle B = 7x-26. You can set up the equation A + B = 180, and then plug in angles A and B, which gives you 7x+10 + 7x-26 = 180. Then you just need to isolate x:

Combine like terms: 14x - 16 = 180

Add 16 to both sides: 14x = 196

Divide both sides by 14: x = 14

Now that you know x, you can plug it into the expression for angle A (7x+10):

A = 7(14) + 10 = 98+10 = 108

5 0
2 years ago
huong and kathyrn each day impeoved their yards by planting rose bushes and ornamental grass. they bought their supplies from th
marta [7]

Answer:

One rose bush = $3

One bunch of ornamental grass = $4

Step-by-step explanation:

We can set up a system of equations to solve for this. Let cost of 1 rose bush be r and cost of 1 ornamental grass be g. Thus we can form 2 equations:

14r+7g=70\\5r+14g=71

We can multiply the first equation by -2 so that we can eliminate g. Thus, we have:

(*-2)14r+7g=70\\5r+14g=71\\-------\\-28r-14g=-140\\5r+14g=71\\--------\\-23r=-69\\r=\frac{-69}{-23}=3

Thus, 1 rose bush is $3. Now plugging in r = 3 into the first original equation, we can solve for g:

14r+7g=70\\14(3)+7g=70\\42+7g=70\\7g=70-42\\7g=28\\g=\frac{28}{7}=4

Thus, 1 bunch of ornamental grass is $4.

5 0
3 years ago
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