The first term, a, is 2. The common ratio, r, is 4. Thus,
a_(n+1) = 2(4)^(n).
Check: What's the first term? Let n=1. Then we get 2(4)^1, or 8. Is that correct? No.
Try this instead:
a_(n) = a_0*4^(n-1). Is this correct? Seeking the first term (n=1), does this formula produce 2? 2*4^0 = 2*1 = 2. YES.
The desired explicit formula is a_(n) = a_0*4^(n-1), where n begins at 1.
-7/3, -3/4, 0.5, 2/3, 1.2
Brainliest please
Answer:
No. See explanation below.
Step-by-step explanation:
Since the cards are being selected <u>without replacement,</u> every time we select a card, <u>the probability varies</u> (since there is one less card) and therefore, the probability doesn't remain the same for every trial and therefore, the probability of success changes for every trial.
It is because of this that this probability experiment doesn't represent a binomial experiment.
