Can someone answer this question, and give me the work?
1 answer:
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Answer:
65.3%
Step-by-step explanation:
Binomial distribution PMF below (along with a description)
the probabilty of getting 2, 3, or 4 successes in 5 trials is just
p(2)+p(3)+p(4)
p(2)= 5C2*.4²*(1-.4)³ = .3456
p(3)= 5C3*.4³*(1-.4)²= .2304
p(4)= 5C4*.4⁴*(1-.4)=.0768
.3456+.2304+.0768= .6528
The experimental probability is, as the name suggests, a probability based on observation. If we say that the experimental probability of seeing a hawk at the Avian Viewing Center on any given day is 20%, it means that someone has visited the center for many days, and at the end of this experiment he has met hawks on 20% of the days, i.e. one out of five days.
If we assume that these measurement are trustworthy, we can assume that Allison will also see a hawk on one fifth of the days.
Since she will visit the center for 240, she should expect to see a hawk on one fifth of these days, i.e.
days.