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gladu [14]
3 years ago
13

The charitable foundation for a large metropolitan hospital is conducting a study to characterize its donor base. In the past, m

ost donations have come from relatively wealthy individuals; the average annual donor income in the most recent survey was right at $100,000. The foundation believes the average has now increased. A random sample of 200 current donors showed a mean annual income of $103,157 and a standard deviation of $27,498. To perform this study, we should form a null hypothesis stating that the average is
Mathematics
1 answer:
In-s [12.5K]3 years ago
8 0

Answer:

The null hypothesis will be that the average annual donor income is less or equal to $ 100,000

Step-by-step explanation:

The claim is mostly treated as alternate hypothesis .

In this question the claim is given as the average annual donor income has increased therefore it is written as

Ha: u > 100,000

The null hypothesis is reverse of the alternate hypothesis

H0: u ≤ 100,000

The null hypothesis will be that the average annual donor income is less or equal to $ 100,000

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Please Please please
Nadusha1986 [10]

Answer:

is the name of your account from little mermaid?  :DDD

Step-by-step explanation:

Use SOH CAH TOA to recall how the trig functions fit on a triangle

SOH: Sin(Ф)= Opp / Hyp

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now just refer to the above ( also copy and paste the above on your computer some where so you have it always)

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4 0
3 years ago
The owner of a local golf course wants to estimate the difference between the scores of golfers on his golf course and the score
Olenka [21]

Answer:

(8) The correct option is (3).

(2) The correct option is (1).

Step-by-step explanation:

(8)

The hypothesis can be defined as:

<em>H₀</em>: There is no difference between the two population means, i.e. <em>μ₁ </em>= <em>μ₂</em>.

<em>Hₐ</em>: There is a difference between the two population means, i.e. <em>μ₁ </em>≠ <em>μ₂</em>.

The decision rule of the test based on confidence interval is:

If the (1 - <em>α</em>) % confidence interval consists the null hypothesis value then the null hypothesis is not rejected. and vice-versa.

The 90% confidence interval for the paired difference between means is, (-3.31, 14.74).

The interval consists the null value, 0.

Thus, the null hypothesis was failed to be rejected.

<u>Conclusion:</u>

No significant difference exists between the average difference in scores and the differences were calculated as 0.

Thus, the correct option is (3).

(2)

A (1 - <em>α</em>) % confidence interval implies that there is (1 - <em>α</em>) % chance of the population parameter to be contained in this interval.

Or if 100 such intervals are constructed then (1 - <em>α</em>) of these intervals will consist the true parameter value.

The 99% confidence interval for the difference between means is, (-0.124, 13.85).

This interval implies that the true mean difference between the two populations lies in this interval with probability 0.99.

<u>Conclusion:</u>

We are 99% confident that the difference between the average age of all men and all women who play golf at the course is between -0.124 and 13.85.

Thus, the correct option is (1).

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