All categories

3 years ago

100 Brainly points!!!!

Mathematics

1 answer:

worty [1.4K]3 years ago

5 0

Answer:

Point A’ is at (-2,-2)

& point D' is at (4,-2)

Step-by-step explanation:

Point A’ => (-1×2, -1×2) => (-2 , -2)

Point D' => (2×2 , -1×2) => (4 , -2)

You might be interested in

Need help with this math problem

elena-14-01-66 [18.8K]

Answer:

Sangayko venchitra ko asalokan gari nimna samuhko ganatmak sankhya Pata lagaunuhos

N(A)

3 0

3 years ago

Hans deposits $300 into an account that pays simple interest at a rate of 2% per year. How much interest will he be paid in the

blagie [28]

300 x 0.02 x 5 = 30
answer
 interest will $30 in the first 5 years

5 0

3 years ago

Boxes of raisins are labeled as containing 22 ounces. Following are the weights, in the ounces, of a sample of 12 boxes. It is r

ZanzabumX [31]

Answer:

A 90% confidence interval for the mean weight is [21.78 ounces, 21.98 ounces].

Step-by-step explanation:

We are given the weights, in the ounces, of a sample of 12 boxes below;

Weights (X): 21.88, 21.76, 22.14, 21.63, 21.81, 22.12, 21.97, 21.57, 21.75, 21.96, 22.20, 21.80.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean weight = $\frac{\sum X}{n}$ = 21.88 ounces

s = sample standard deviation = $\sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }$ = 0.201 ounces

n = sample of boxes = 12

$\mu$ = population mean weight

Here for constructing a 90% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation.

So, 90% confidence interval for the population mean, $\mu$ is ;

P(-1.796 < $t_1_1$ < 1.796) = 0.90 {As the critical value of t at 11 degrees of

freedom are -1.796 & 1.796 with P = 5%}

P(-1.796 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 1.796) = 0.90

P( $-1.796 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $1.796 \times {\frac{s}{\sqrt{n} } }$ ) = 0.90

P( $\bar X-1.796 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+1.796 \times {\frac{s}{\sqrt{n} } }$ ) = 0.90

90% confidence interval for $\mu$ = [ $\bar X-1.796 \times {\frac{s}{\sqrt{n} } }$ , $\bar X+1.796 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $21.88-1.796 \times {\frac{0.201}{\sqrt{12} } }$ , $21.88+1.796 \times {\frac{0.201}{\sqrt{12} } }$ ]

= [21.78, 21.98]

Therefore, a 90% confidence interval for the mean weight is [21.78 ounces, 21.98 ounces].

8 0

3 years ago

What is the vertex of y=3|x+1|-2

spin [16.1K]

Answer:

(-1,-2)

Step-by-step explanation:

Generally, the absolute value function can be expressed like so:

f(x) = y = a|x-h|+k, where vertex: (h,k)

Rewriting our function here ever so slightly gives us: y = 3|x-(-1)|+(-2)

So the vertex is at (-1,-2)

7 0

3 years ago

CAN SOMEONE HELP ME PLEASE ASAP!?

VikaD [51]

Answer:

40°

Step-by-step explanation:

∠AOE and ∠COD are vertical angles meaning they have the same value.

8 0

3 years ago