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Alina [70]
3 years ago
11

100 Brainly points!!!!

Mathematics
1 answer:
worty [1.4K]3 years ago
5 0

Answer:

Point A’ is at (-2,-2)

& point D' is at (4,-2)

Step-by-step explanation:

Point A’ => (-1×2, -1×2) => (-2 , -2)

Point D' => (2×2 , -1×2) => (4 , -2)

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!!!PLEASE HELPPPPPP ILL DO WHATEVER!!! ILL GIVE >>BRAINLIEST<
Rufina [12.5K]

Answer:

x >2.2034

Step-by-step explanation: hope this helps :)

3 0
3 years ago
Round off 24.67 to one significant
marishachu [46]
24.67 rounded to one significant figure would be 25.
4 0
3 years ago
Read 2 more answers
Some 1 plz HELP!<br> 3 5/6 X 4 4/5<br> (plz include instructions if u can thx!)
rewona [7]
Well convert 3 5/6 to 23/6 and 4 4/5 to 24/ 5
then find a multiple that both 5 and 6 have which is 30
23x5= 115 and 24x6= 144
so 115 x 144= 16560/30
16560/30 = 552 /1 so your answer is 
552
8 0
3 years ago
Read 2 more answers
What is the factorization of 729^15+1000?
igomit [66]

Answer:

The factorization of 729x^{15} +1000 is (9x^{5} +10)(81x^{10} -90x^{5} +100)

Step-by-step explanation:

This is a case of factorization by <em>sum and difference of cubes</em>, this type of factorization applies only in binomials of the form (a^{3} +b^{3} ) or (a^{3} -b^{3}). It is easy to recognize because the coefficients of the terms are <u><em>perfect cube numbers</em></u> (which means numbers that have exact cubic root, such as 1, 8, 27, 64, 125, 216, 343, 512, 729, 1000, etc.) and the exponents of the letters a and b are multiples of three (such as 3, 6, 9, 12, 15, 18, etc.).

Let's solve the factorization of 729x^{15} +1000 by using the <em>sum and difference of cubes </em>factorization.

1.) We calculate the cubic root of each term in the equation 729x^{15} +1000, and the exponent of the letter x is divided by 3.

\sqrt[3]{729x^{15}} =9x^{5}

1000=10^{3} then \sqrt[3]{10^{3}} =10

So, we got that

729x^{15} +1000=(9x^{5})^{3} + (10)^{3} which has the form of (a^{3} +b^{3} ) which means is a <em>sum of cubes.</em>

<em>Sum of cubes</em>

(a^{3} +b^{3} )=(a+b)(a^{2} -ab+b^{2})

with a= 9x^{5} y b=10

2.) Solving the sum of cubes.

(9x^{5})^{3} + (10)^{3}=(9x^{5} +10)((9x^{5})^{2}-(9x^{5})(10)+10^{2} )

(9x^{5})^{3} + (10)^{3}=(9x^{5} +10)(81x^{10}-90x^{5}+100)

.

8 0
3 years ago
What is the value of the following expression? <br> 7+18/(6-3)
daser333 [38]
7+18/(6-3)
7+18/3
25/3=8.333
5 0
3 years ago
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