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marin [14]
3 years ago
13

The MTC Theater holds 250 people, and last night’s performance sold out!  Students paid $3.00 per ticket, while adults paid $5.0

0 per ticket.  Last night’s show brought in $1050.
Write a system of equations for the problem.
Mathematics
1 answer:
Lilit [14]3 years ago
3 0

9514 1404 393

Answer:

  • s + a = 250
  • 3s + 5a = 1050

Step-by-step explanation:

Let s and a represent the numbers of student and adult tickets sold. The system of equations that can be written from the given information is ...

  s + a = 250 . . . . . . total of tickets sold

  3s +5a = 1050 . . . dollar value of tickets sold

_____

The solution is (s, a) = (100, 150). 100 student tickets and 150 adult tickets were sold.

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Which equation models the problem below if c represents the number of puppies whose eyes are closed?
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First you must take into account the variable that is being defined for this case:
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Solve for aaa: a-\left(-3.75\right)=6.11a−(−3.75)=6.11a, minus, left parenthesis, minus, 3, point, 75, right parenthesis, equals
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Answer:

Step-by-step explanation:

                              To isolate <em>a</em>, we add -3.75 to both sides.

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4 0
3 years ago
The lengths of two sides of a triangle are 10 and 24, and the third side is x. How many whole number values are possible for x.
solong [7]

Answer:

20.

Step-by-step explanation:

In any triangle, the sum of the lengths of any two sides should be strictly greater than the length of the third side. For example, if the length of the three sides are a, b, and c:

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a + c > b, and

b + c > a.

In this question, the length of the sides are 10, 24, and x. The length of these sides should satisfty the following inequalities:

10 + 24 > x,

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Since x > 0, the inequality 24 + x > 10 is guarenteed to be satisfied.

Simplify 10 + 24 > x to obtain the inequality x < 35.

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Since x needs to be a whole number, the greatest x that satisfies x < 35 would be 34. Similarly, the least x\! that satisfies x > 14 would be 15. Thus, x\!\! could be any whole number between 15\! and 34\! (inclusive.)

There are a total of 34 - 15 + 1 = 20 distinct whole numbers between 15 and 34 (inclusive.) Thus, the number of possible whole number values for x would be 20.

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2 years ago
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