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Zielflug [23.3K]
3 years ago
14

100 points / please help

Mathematics
2 answers:
creativ13 [48]3 years ago
7 0

Answer:

{\huge\red{\fbox{{࿐αɴѕωєя࿐}}}}

<h2><u>Recipe </u><u>A:</u></h2>

Cups of flour used = 3

Rolls made = 12

Cups of flour per roll

=  \frac{3}{12}  \\  =  \frac{1}{4}   \\  = 0.25

<h2><u>Recipe </u><u>B:</u></h2>

Cups of flour used = 5

Rolls made = 24

Cups of flour per roll

\frac{5}{24}  \\  = 0.20

<h2><u>Recipe </u><u>C:</u></h2>

Cups of flour used = 11

Rolls made = 48

Cups of flour per roll

\frac{11}{48}  \\  = 0.22

<h3>Now compare Recipe A, B & C.</h3>

0.25 > 0.22 > 0.20

Recipe A > Recipe C > Recipe B.

✏ So, <u>Recipe </u><u>A</u><u> </u>used the most cups of flour per roll (option a).

ʰᵒᵖᵉ ⁱᵗ ʰᵉˡᵖˢ

\huge\blue{ \mid{ \underline{ \overline{ \tt ꧁❣ RainbowSalt2222 ࿐ }} \mid}}

andre [41]3 years ago
6 0

Answer:

Recipe A

Step-by-step explanation:

Hope this helped!!!

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Hi please help i’ll give brain
NARA [144]

Answer:

The GCF is going to be 20

Step-by-step explanation:

This Is how I find the GCF of 2 numbers. I find the prime factorization first, then I find the common factors and multiply them. Here

The prime factorization of 20, 2 × 2 × 5= 20

The prime factorization of 80, 2 × 2 × 2 × 2 × 5 = 80

The common factors are 2, 2, and 5. We multiply those to get the GCF.

2 × 2 × 5 = 20

7 0
3 years ago
Read 2 more answers
Which is the first step in simplifying the expression 2(x + 3) + 5?
mina [271]
I believe the answer would be B
5 0
3 years ago
Suppose two dice are tossed and the numbers on the upper faces are observed. Let S denote the set of all possible pairs that can
Thepotemich [5.8K]

Answer:

▪A = {(1,2) (1,4) (1,6) (2,2) (2,4) (2,6) (3,2) (3,4) (3,6) (4,2) (4,4) (4,6) (5,2) (5,4) (5,6) (6,2) (6,4)(6,6)}

▪C bar = {(2,2) (2,4) (2,6) (4,2) (4,4) (4,6) (6,2) (6,4) (6,6)}

▪A∩B = {(2,2) (2,4) (2,6) (4,2) (4,4) (4,6) (6,2) (6,4) (6,6)}

▪A∩B bar = {(1,2) (1,4) (1,6) (3,2) (3,4) (3,6) (5,2) (5,4) (5,6)}

▪A bar∪B = {(1,1) (1,3) (1,5) (2,1) (2,2) (2,3) (2,4) (2,5) (2,6) (3,1) (3,3) (3,5) (4,1) (4,2) (4,3) (4,4) (4,5) (4,6) (5,1) (5,3) (5,5) (6,1) (6,2) (6,3) (6,4) (6,5) (6,6)}

▪A bar∩C = {(1,1) (1,3) (1,5) (2,1) (2,3) (2,5) (3,1) (3,3) (3,5) (4,1) (4,3) (4,5) (5,1) (5,3) (5,5) (6,1) (6,3) (6,5)}

Step-by-step explanation:

S = {(1,1) (1,2) (1,3) (1,4) (1,5) (1,6) (2,1) (2,2) (2,3) (2,4) (2,5) (2,6) (3,1) (3,2) (3,3) (3,4) (3,5) (3,6) (4,1) (4,2) (4,3) (4,4) (4,5) (4,6) (5,1) (5,2) (5,3) (5,4) (5,5) (5,6) (6,1) (6,2) (6,3) (6,4) (6,5) (6,6)}

A = {(1,2) (1,4) (1,6) (2,2) (2,4) (2,6) (3,2) (3,4) (3,6) (4,2) (4,4) (4,6) (5,2) (5,4) (5,6) (6,2) (6,4)(6,6)} (second die is even)

B = {(1,1) (1,3) (1,5) (2,2) (2,4) (2,6) (3,1) (3,3) (3,5) (4,2) (4,4) (4,6) (5,1) (5,3) (5,5) (6,2) (6,4) (6,6)} (sum of the two numbers is even)

C = {(1,1) (1,2) (1,3) (1,4) (1,5) (1,6) (2,1) (2,3) (2,5) (3,1) (3,2) (3,3) (3,4) (3,5) (3,6) (4,1) (4,3) (4,5) (5,1) (5,2) (5,3) (5,4) (5,5) (5,6) (6,1) (6,3) (6,5)} (at least one in the pair is odd i.e one of the pair is odd or both are odd)

A bar = {(1,1) (1,3) (1,5) (2,1) (2,3) (2,5) (3,1) (3,3) (3,5) (4,1) (4,3) (4,5) (5,1) (5,3) (5,5) (6,1) (6,3) (6,5)} (the pairs that are not in A)

B bar = {(1,2) (1,4) (1,6) (2,1) (2,3) (2,5) (3,2) (3,4) (3,6) (4,1) (4,3) (4,5) (5,2) (5,4) (5,6) (6,1) (6,3) (6,5)} (the pairs that are not in B)

C bar = {(2,2) (2,4) (2,6) (4,2) (4,4) (4,6) (6,2) (6,4) (6,6)} (the pairs that are not in C)

▪A = {(1,2) (1,4) (1,6) (2,2) (2,4) (2,6) (3,2) (3,4) (3,6) (4,2) (4,4) (4,6) (5,2) (5,4) (5,6) (6,2) (6,4)(6,6)}

▪C bar = {(2,2) (2,4) (2,6) (4,2) (4,4) (4,6) (6,2) (6,4) (6,6)}

▪A∩B = {(2,2) (2,4) (2,6) (4,2) (4,4) (4,6) (6,2) (6,4) (6,6)} (intersection: the pairs that are common to both A and B)

▪A∩B bar = {(1,2) (1,4) (1,6) (3,2) (3,4) (3,6) (5,2) (5,4) (5,6)} (intersection: the pairs that are common to both A and B bar)

▪A bar∪B = {(1,1) (1,3) (1,5) (2,1) (2,2) (2,3) (2,4) (2,5) (2,6) (3,1) (3,3) (3,5) (4,1) (4,2) (4,3) (4,4) (4,5) (4,6) (5,1) (5,3) (5,5) (6,1) (6,2) (6,3) (6,4) (6,5) (6,6)} (union: all the pairs in A bar and B )

▪A bar∩C = {(1,1) (1,3) (1,5) (2,1) (2,3) (2,5) (3,1) (3,3) (3,5) (4,1) (4,3) (4,5) (5,1) (5,3) (5,5) (6,1) (6,3) (6,5)} (intersection: the pairs that are common to both A bar and C)

6 0
3 years ago
The diagonals of a kite _____.
Vikentia [17]

Answer:

A. Meet at a right angle.

Step-by-step explanation:

We should know the properties of kite.

(1) The diagonals of a kite meet at a right angle.

(2) Kites have exactly one pair of opposite angles that are congruent.

Therefore, the answer is A. Meet at a right angle.

Thank you.

5 0
3 years ago
Kris is 2 meters tall and casts a shadow
postnew [5]

The tree is 20 m tall .

Step-by-step explanation:

<h2>Given : </h2>
  • 2m tall tree cast a shadow 4 m long .

=> 2 m tree = 4 m long

If we find shadow of 1 m tall tree = 4/2

=> we have to find height of 10 m tall tree which is .. = 4/2 × 10 = > 20 m

6 0
2 years ago
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