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DENIUS [597]
2 years ago
14

Can someone please help me with this question?

Mathematics
1 answer:
amid [387]2 years ago
4 0

Answer:

Answer: Function A is represented by the quadrant

Step-by-step explanation:

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I need help with number 8 please. if you don't mind can you show your work so I know how to do it? Thanks in advance! :)
Trava [24]
You have to divide both sides by 5 because it states"5t" and you should get "t=20"
7 0
3 years ago
Help me pls its due soon
RoseWind [281]

Answer:

do you mean in simplist form?? if so...

Step-by-step explanation:

5/7=5/7

2/6=1/3

7 0
3 years ago
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What is the least common multiple of 12, 18, and 45?
Basile [38]

Answer:

180

Step-by-step explanation:

7 0
3 years ago
(4+3) 2 +5= <br> pls tell me i have no idea
horrorfan [7]

Answer:

19

Step-by-step explanation:

(4+3)2+5=

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4 0
3 years ago
Could someplease explain the whole problem? For the first part my the answer I got was x= .618, -.618, and <img src="https://tex
algol13

9514 1404 393

Answer:

  a) x = (√5 -1)/2 ≈ 0.618034

  b) 1/x = (√5 +1)/2 ≈ 1.618034

Step-by-step explanation:

<u>Given</u>:

  x/(1 -x) = 1/x

<u>Find</u>:

  Exactly, and as a decimal approximation, ...

  a) x, using the quadratic formula

  b) 1/x

<u>Solution</u>:

a) We can multiply the given equation by x(1 -x) to obtain ...

  x² = 1 -x

  x² +x -1 = 0 . . . . . . add x-1

The coefficients for use in the quadratic formula are a=1, b=1, c=-1. The solution using the quadratic formula is ...

  x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}=\dfrac{-1\pm\sqrt{1^2-4\cdot1\cdot(-1)}}{2\cdot1}=\dfrac{-1\pm\sqrt{5}}{2}

We are only interested in the positive solution, which is ...

  \boxed{x=\dfrac{\sqrt{5}-1}{2}\approx0.618034}

__

b) The quadratic we developed in the first part can be rearranged like this:

  x² +x = 1 . . . . . . add 1 to both sides

  x(x +1) = 1 . . . . . factor out x

  x +1 = 1/x . . . . . .divide by x

Then to find the value of 1/x, we simply need to add 1 to the value of x we have:

  \dfrac{1}{x}=\dfrac{\sqrt{5}-1}{2}+1=\dfrac{\sqrt{5}-1}{2}+\dfrac{2}{2}=\dfrac{\sqrt{5}-1+2}{2}\\\\\boxed{\dfrac{1}{x}=\dfrac{\sqrt{5}+1}{2}\approx1.618034}

5 0
2 years ago
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