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dolphi86 [110]
3 years ago
10

Help please due at 11:59!!!

Mathematics
1 answer:
Elis [28]3 years ago
8 0
I think the answers b i'm just answering questions tho idk if that's right
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Which of the following statements about the points (-4,6) and (4,-6) are true
gtnhenbr [62]

Answer:

c

Step-by-step explanation:

3 0
3 years ago
Show me how much to shade
Gnoma [55]
If you're talking about inequality graphs, you shade the area where any point in the shaded area can solve the inequality, if I remember correctly. I can't exactly show you how much to shade.
3 0
3 years ago
Cedric completed the square for the quadratic expression 5x^2−40x+15 in order to determine the minimum value of the expression,
Olegator [25]

Answer:

Step 3 is not correct (should be (x-4)^2, not (x+4)^2

Step-by-step explanation:

The expression that we have to simplify is:

5x^2-40x+15

We proceed step-by-step, in order to find the mistake did by Cedric:

1) First, we factorize the 5 outside:

5(\frac{5x^2}{5}-\frac{40x}{5}+\frac{15}{5})=5(x^2-40x+3) --> this step is correct

2) We add +16 and -16 inside the brackets:

5(x^2-8x+16-16+3) --> this step is correct

3) We rewrite the term (x^2-8x+16) as the square of a bynomial, which is (x-4)^2, so the expression becomes

5((x-4)^2-16+3) --> we notice that this step is wrong: in fact, Cedric wrote (x+4)^2, which is not correct.

4) Now we continue: we rewrite -16+3 as -13,

5((x-4)^2-13)

5) Finally, we multiply the 5 by the terms in the bracket:

=5(x-4)^2-65

5 0
3 years ago
Construct a 90% confidence interval for μ1-μ2 with the sample statistics for mean calorie content of two​ bakeries' specialty pi
DIA [1.3K]

Answer:

The 90% confidence interval for the difference in mean (μ₁ - μ₂) for the two bakeries is; (<u>49</u>) < μ₁ - μ₂ < (<u>289)</u>

Step-by-step explanation:

The given data are;

Bakery A

\overline x_1<em> </em>= 1,880 cal

s₁ = 148 cal

n₁ = 10

Bakery B

\overline x_2<em> </em>= 1,711 cal

s₂ = 192 cal

n₂ = 10

\left (\bar{x}_1-\bar{x}_{2}  \right ) - t_{c}\cdot \hat \sigma \sqrt{\dfrac{1}{n_{1}}+\dfrac{1}{n_{2}}}< \mu _{1}-\mu _{2}< \left (\bar{x}_1-\bar{x}_{2}  \right ) + t_{c}\cdot \hat \sigma \sqrt{\dfrac{1}{n_{1}}+\dfrac{1}{n_{2}}}

df = n₁ + n₂ - 2

∴ df = 10 + 18 - 2 = 26

From the t-table, we have, for two tails, t_c = 1.706

\hat{\sigma} =\sqrt{\dfrac{\left ( n_{1}-1 \right )\cdot s_{1}^{2} +\left ( n_{2}-1 \right )\cdot s_{2}^{2}}{n_{1}+n_{2}-2}}

\hat{\sigma} =\sqrt{\dfrac{\left ( 10-1 \right )\cdot 148^{2} +\left ( 18-1 \right )\cdot 192^{2}}{10+18-2}}= 178.004321469

\hat \sigma ≈ 178

Therefore, we get;

\left (1,880-1,711  \right ) - 1.706\times178 \sqrt{\dfrac{1}{10}+\dfrac{1}{18}}< \mu _{1}-\mu _{2}< \left (1,880-1,711  \right ) + 1.706\times178 \sqrt{\dfrac{1}{10}+\dfrac{1}{18}}

Which gives;

169 - \dfrac{75917\cdot \sqrt{35} }{3,750} < \mu _{1}-\mu _{2}< 169 + \dfrac{75917\cdot \sqrt{35} }{3,750}

Therefore, by rounding to the nearest integer, we have;

The 90% C.I. ≈ 49 < μ₁ - μ₂ < 289

4 0
3 years ago
Felecia works for a furniture company. She earns a base salary of $300 per week, then 4% commission on sales. How much will she
Anni [7]

Answer:

i think

Step-by-step explanation:

4 0
3 years ago
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