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MariettaO [177]
3 years ago
15

Please answer this question correct now fast

Mathematics
1 answer:
Tom [10]3 years ago
8 0

Answer: 14.1

Step-by-step explanation:

Law of cosines:

d^2 = 8^2 + 10^2 - 2(8)(10)cos103

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Yuki888 [10]
X=3
r<span>≥8
n=6
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3 0
3 years ago
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Find an equation that models the path of a satellite if its path is a hyperbola, a = 55,000 km, and c= 81,000 km. Assume the cen
elena-14-01-66 [18.8K]

Answer:

\frac{x^2}{55000^2} - \frac{y^2}{59464^2} =1

Step-by-step explanation:

the transverse axis is horizontal.

so its a horizontal hyperbola

Center is the origin so center is (0,0)

Equation of horizontal hyperbola is

\frac{x^2}{a^2} - \frac{y^2}{b^2} =1

Given a= 55000 and c= 81000

c^2 = a^2 + b^2

81000^2 = 55000^2 + b^2

subtract 55000^2 on both sides

b  = sqrt(81000^2 - 55000^2)= 59464.27

now plug in the values

\frac{x^2}{55000^2} - \frac{y^2}{59464^2} =1

7 0
3 years ago
The HCP prescribes methotrexate 7.5 mg PO weekly, in 3 divides doses for a child with rheumatoid arthritis whose body surface ar
dexar [7]

Answer:

1.5mg

Step-by-step explanation:

From the question, we are told that the HCP prescribed 7.5 mg of PO weekly

The therapeutic dosage is given in the question as 5 - 15 mg/m² weekly.

The child's body surface area is given = 0.6m²

The mg of PO that the nurse should administer in each of the three doses given weekly is calculated as

7.5mg/ 5mg/m²

= 1.5 mg of PO

4 0
3 years ago
A cyclist rides his bike at a rate of 10 kilometers per hour. What is this rate in miles per hour. How many miles will the cycli
poizon [28]

Answer:

10 km/ hour = 6.25 miles/ hour

Step-by-step explanation:

cyclist travel in 5 hours = 6.25 x 5 = 31.25 miles

8 0
3 years ago
Find the angle θ between u = &lt;7, –2&gt; and v = &lt;–1, 2&gt;.
Dmitry_Shevchenko [17]

The angle between two vectors is:

CosФ = u - v / Magnitude(u) x magnitude(v)

Magnitude of u = SQRT(7^2 + -2^2) = SQRT(49 +4) = SQRT(53)

Magnitude of v = SQRT(-1^2 +2^2) = SQRT(1 +4) = SQRT(5)

u x v = (7 x -1) + (-2 x 2) = -7 + -4 = -11

cosФ = -11 / sqrt(53) x sqrt(5)

cosФ = -11sqrt265) / 265

Ф =cos^-1(-11sqrt265) / 265)

Ф=132.51 degrees.

7 0
3 years ago
Read 2 more answers
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