Question

I NEED HELP PLEASE! First to give the work required gets brainliest +50 points! Image of the shape is attached. Each face of the cube is 5cm! Part B
After the paint dries, Jackson cuts the cube in half. He makes the cut along the diagonal of one pair of
parallel faces. Rounded to the nearest thousandth, the diagonal has a length of 7.071 centimeters. Once
the cut is made, Jackson has two identical triangular prisms.
What is the combined area, in square centimeters, of the surfaces of the two prisms that were not painted?
Show your work!

Answer 1

Answer:

• 70.71 cm²

Step-by-step explanation:

There are two faces that are not painted.

They are rectangles with one side 5 cm, and another side 7.071 cm.

Total of not painted surface area is:

• 2*5*7.071 = 70.71 cm²

Answer 2

Answer:

$\Large \boxed{\sf 70.71 \ cm^2}$

Step-by-step explanation:

Jackson had previously painted 6 faces of the cube.

The unpainted faces are the 2 faces inside the cube that is made when the cube is cut.

Area of the unpainted section is required.

The 2 faces are rectangles

$2 \times (5 \times 7.071)=70.71 \ \sf cm^2$