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Bas_tet [7]
3 years ago
6

(Q2) Which of the following points lies on the graph of the function y = 4x ?

Mathematics
1 answer:
stepladder [879]3 years ago
5 0

Answer:

C

Step-by-step explanation:

I think I will answer the question the your attachment because it has full information.

The function is: y = 3*2^{x}

a. The function decreases

Wrong, because the base number is 2 and it is greater than 0. The function will go up

b. y=intercept of  (0.2)

Wrong, Let substitute x =2 into the function: y = 3*2^{2} = 12  

c. if x increase by 1, the value of y will double

Because the base number is 2. For example:

  • If x = 2, y = 3*2^{2}  = 12
  • If x =3, y =3*2^{3} =(3*2^{2}*)2  = 24

d. contains the point (2,4)

Wrong, Let substitute x =4 into the function: y = 3*2^{4} = 48

So we choose C

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Option (B) is the correct answer to the following question.

Step-by-step explanation:

Step-1: We have to find the Mean of the series.

The series is Given in the question 62 61 61 57 61 54 59 58 59 69 60 67.

Mean(\overline{x})=\frac{62+61+61+57+61+54+59+58+59+69+60+67}{12} = 60.67

Step-2: We have to find the Standard Deviation.

Let Standard Deviation be x.

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Put value in formula of Standard Deviation,

s= \sqrt{\frac{(62+60.67)^{2}+(61+60.67)^{2}+(61+60.67)^{2}+(57+60.67)^{2}+....(67+60.67)^{2}}{n-1}} = 40.75

Step-3: Then, we have to find the critical value by chi-square.

X_{1-\alpha/2}^{2}=3.82

X_{1-\alpha/2}^{2}=21.92

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\sqrt{\frac{(n-1).s^2}{X_{\alpha/2}^{2}} } = \sqrt{\frac{12-1}{21.92}.(4.075)^2 }\approx2.8868 \\ i.e 2.9

\sqrt{\frac{(n-1).s^2}{X_{\alpha/2}^{2}} } = \sqrt{\frac{12-1}{3.816}.(4.075)^2 }\approx6.9188 \\ i.e 6.9

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3 years ago
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