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Ainat [17]
3 years ago
15

A rectangular conatainer with a square base is 2/3 full of water. This water is used to fill some small containers how many smal

l containers can it fill
Mathematics
1 answer:
vivado [14]3 years ago
6 0

Answer:

5 small containers will be  required and used.

This water is used to fill four and half  small containers exactly.

4.5 small containers

Step-by-step explanation:

The rectangular container has dimensions 12*12*45 cm  and the small container has dimensions 6*5*8 cm

The rectangular container with a square base is 2/3 full of water.The height is used up to 45*2/3= 7.5 cm

The volume of the water in the rectangular container with a square base is

12*12*7.5= 1080 cm³

The volume of the water in the smaller container is

6*5*8= 240 cm³

Number of smaller containers required = Volume of large container / Volume of smaller container

Number of smaller containers required =1080 cm³/240 cm³= 4.5

This water is used to fill four and half  small containers exactly.

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It means that all values of x would make it true. Also take a look at the equation when we simplify:

4x + 7 = 1 + 4x + 6
Which simplified turns into
4x + 7 = 4x + 7

So no matter what value you put for x, it will be the same on both sides, making all values true for x.
5 0
3 years ago
Please help me thanks!
Sliva [168]

Answer: See the screenshot below.

Explanation:

We'll be using these trig functions

  • sine = opposite/hypotenuse
  • cosine = adjacent/hypotenuse
  • tangent = opposite/adjacent

The inverse of those help us find the angle. Notation like arcsine is the same as inverse sine denoted as \sin^{-1} on many calculators.

The decimal results are approximate.

7 0
2 years ago
A
telo118 [61]

Answer:

1 La longitud de las nuevas cuerdas = 5 metros y 9 metros

2 El costo de las paletas = $ 3

El costo de las gomitas = $ 3

Step-by-step explanation:

1) Sea la primera mitad de la cuerda representada por = a

Deje que la segunda mitad de la parte superior esté representada por = b

a + b = 14 metros

De la pregunta, se nos dice que ok, la mitad es 4 metros más larga que la otra

a = b + 4

Por lo tanto

b + 4 + b = 14 metros

2b + 4 = 14 metros

2b = 14 - 4

b = 10/2

b = 5 metros

a = b + 4

a = 5+ 4

a = 9 metros

Por lo tanto, la longitud de las nuevas cuerdas = 5 metros y 9 metros

2)

Representemos el costo de las paletas = p

Costo de gomitas = g

De la pregunta 2 se nos dice que:

Tu vas a la tienda con un amigo y compras 6 paletas y 2 gomitas. Si tú pagas $ 24

Por tanto: 6p + 2g = 24 ....... Ecuación 1

Tu amigo pide 1 paleta y 10 gomitas. y tu amigo $ 33

p + 10g = 33 ....... Ecuación 2

p = 33 - 10g

Sustituya p por 33 - 10g en la Ecuación 1

6p + 2g = 24 ....... Ecuación

6 (33-10 g) + 2 g = 24

198 - 60 g + 2 g = 24

-58g = 24-198

-58g = - 174

g = -174 / -58

g = $ 3

Para encontrar p

p = 33 - 10g

p = 33 - 10 × 3

p = 33 - 30

p = $ 3

Por lo tant,

El costo de las paletas = $ 3

El costo de las gomitas = $ 3

6 0
3 years ago
In a box there are 50 counters :white ones,blue ones and red ones .There are eleven times as many white ones as blue ones.There
lions [1.4K]

Answer:

Find the question mark using the model I've provided and that'll be the answer!

4 0
3 years ago
Read 2 more answers
Kindly Only Answer if you know how to do this problem:
steposvetlana [31]
Its representedf by 2 polygons(triangles)
first one :
24-20=4
11-6=5
second:
24-14=10
11-7=4
B. frind area of 2 small trianges
a=(base x height )/2
first=4x5/2=10ft   square
second=10x 4/2=20ft square
add them=10+20=30
rectangle24x 11=264
264-30=234
7 0
3 years ago
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