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2 years ago

What are the solutions to x2 – 10x = 39?

Mathematics

1 answer:

oee [108]2 years ago

7 0

Answer: x=−3 or x=13

Step-by-step explanation:

Step 1: Subtract 39 from both sides.

x2−10x−39=39−39

x2−10x−39=0

Step 2: Factor left side of equation.

(x+3)(x−13)=0

Step 3: Set factors equal to 0.

x+3=0 or x−13=0

x=−3 or x=13

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3 years ago

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3 years ago

Lilian says that 25% of a number will always be less than 75% of any other number. Complete one inequality to support Lillian's

rjkz [21]

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3 years ago

Find the value of x² - x+1 when x=√3 -1, in the form a+b√3 where a and b are integers

lidiya [134]

Answer:

$6-3\sqrt{3}$

If you compare this to $a+b\sqrt{3}$ , then $a=6$ and $b=-3$ .

Step-by-step explanation:

We are given $x=\sqrt{3}-1$ and we are asked to find the value of $x^2-x+1$ .

So we will need to find $x^2$ .

$x=\sqrt{3}-1$

Square both sides:

$x^2=(\sqrt{3}-1)^2$

Expand using identity: $(x-a)^2=x^2-2ax+a^2$ .

$x^2=(\sqrt{3})^2-2(\sqrt{3})(1)+1^2$

$x^2=3-2\sqrt{3}+1$

$x^2=4-2\sqrt{3}$

Let's go back to the full $x^2-x+1$ .

$x^2-x+1$

$(4-2\sqrt{3})-(\sqrt{3}-1)+1$

$4-2\sqrt{3}-\sqrt{3}+1+1$

$6-3\sqrt{3}$

If you compare this to $a+b\sqrt{3}$ , then $a=6$ and $b=-3$ .

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3 years ago

What is the answer to 1-5

34kurt

1. EFG

2. F

3. FA and FB Take a moment to look at this one. The two rays are pointing in opposite directions. They are 180o apart. They share a common point at F.

FE and FG does the same thing.

4. No G is on a line that has only one point on the plane and that point is F.

5, AC has an infinite number of points on the plane.

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3 years ago