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3 years ago

Your boss is impressed with your work and gives you a 3% raise.if the inflation rate is 3% you are

Mathematics

2 answers:

bixtya [17]3 years ago

6 0

<span>B) making about the same amount in today's dollars</span>

kkurt [141]3 years ago

6 0

Answer: The answer is (B) making about the same amount in today's dollars.

Step-by-step explanation: Given that our boss is impressed with our work and give us a 3% raise.

We are to select the correct statement if there is an inflation of 3%.

Since the raise of 3% and inflation rate of 3% occur simultaneously, so there will not be much change in the amount of money we are making in dollars.

Thus, (B) is the correct option.

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Select all the ordered pairs that are solutions to the system.

miv72 [106K]

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WHAT DOES BRAINLEST MEAN???

Step-by-step explanation:

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3 years ago

The point at which the number lines intersect on the coordinate plane is the (origin, x-axis).

eduard

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3 years ago

Angela shared a cab with her friends. When they arrived at their destination, they evenly divided the $j fare among the 3 of the

igor_vitrenko [27]

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3 years ago

Plz help! will mar brainliest.

OleMash [197]

Answer:

From -2<x<-1, the function F(X) is increasing. (B)

Really, it increases all from around -2.5<x<0.5

C is also the second answer, as it increases til around 2.5

It is decreasing from -4<x<-3. But increases right after. It then starts to slow down around x = 1 and go down again.

Which means (B) is your answer.

If you want to get fancy, its a polynomial and if you take the derivative for instantaneous rate, you will see f prime is increasing if you make an example function.

4 0

2 years ago

Read 2 more answers

We are conducting a hypothesis test to determine if fewer than 80% of ST 311 Hybrid students complete all modules before class.

Juli2301 [7.4K]

Answer:

$z=\frac{0.881 -0.8}{\sqrt{\frac{0.8(1-0.8)}{110}}}=2.124$

Null hypothesis: $p\geq 0.8$

Alternative hypothesis: $p < 0.8$

Since is a left tailed test the p value would be:

$p_v =P(Z$

So the p value obtained was a very high value and using the significance level assumed $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis.

Be Careful with the system of hypothesis!

If we conduct the test with the following hypothesis:

Null hypothesis: $p\leq 0.8$

Alternative hypothesis: $p > 0.8$

$p_v =P(Z>2.124)=0.013$

So the p value obtained was a very low value and using the significance level assumed $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis.

Step-by-step explanation:

1) Data given and notation

n=110 represent the random sample taken

X=97 represent the students who completed the modules before class

$\hat p=\frac{97}{110}=0.882$ estimated proportion of students who completed the modules before class

$p_o=0.8$ is the value that we want to test

$\alpha$ represent the significance level

z would represent the statistic (variable of interest)

$p_v{/tex} represent the p value (variable of interest) 2) Concepts and formulas to use We need to conduct a hypothesis in order to test the claim that the true proportion is less than 0.8 or 80%: Null hypothesis:[tex]p\geq 0.8$

Alternative hypothesis: $p < 0.8$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

3) Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.881 -0.8}{\sqrt{\frac{0.8(1-0.8)}{110}}}=2.124$

4) Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level assumed $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a left tailed test the p value would be:

$p_v =P(Z$

Be Careful with the system of hypothesis!

If we conduct the test with the following hypothesis:

Null hypothesis: $p\leq 0.8$

Alternative hypothesis: $p > 0.8$

$p_v =P(Z>2.124)=0.013$

So the p value obtained was a very low value and using the significance level assumed $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis.

5 0

3 years ago