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Blababa [14]
3 years ago
13

What is the length of AB?

Mathematics
1 answer:
frosja888 [35]3 years ago
4 0

Answer:

B. 6

Step-by-step explanation:

We can see that through angles A and C that this triangle is an isosceles triangle. Knowing that, we can set up the equation 3x=4x-2. We can simplify by adding 2 two both sides. We get the equation 3x+2=4x. Then we subtract 3x from both sides. So therefore, 2=x. Length AB is 3x so we would do 2*3, which is equal to 6. So your answer would be B. 6.

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Rita car can travel 35 miles on one gallon of gas she needs she needs to trace 157.5 miles how many gallons of gas will she need
Otrada [13]
You would do 157.5/35 to find how much gas she needs

157/35=4.5
She'll need 4.5gallons of gas
3 0
3 years ago
Solve for x use the completing the square method x^2+6x=5
Mrac [35]

Answer:

x_{1} =-3 +\sqrt{14} \\\\x_{2} =-3 -\sqrt{14}

Step-by-step explanation:

x^{2}+6x-5=0

we divide the coefficient of the X by half :

in this case: 6/2 = 3 , then we do the following

The result obtained is raised to square power:  3^2=9

we sum and subtract by 9 to maintain the balance of the equation:

x^{2}+6x+9-9-5=0

we have:

(x+3)^{2}-9-5=0

(x+3)^{2} = 14

lets apply square root on both sides of the equation:

\sqrt{(x+3)^{2}}=\sqrt{14}

we know:

\sqrt{a^{2}} = abs(a)

so we have:

abs(x+3)=\sqrt{14}

from where two solutions are obtained

x_{1} + 3 =\sqrt{14} \\\\x_{2} + 3 =-\sqrt{14}

finally we have:

x_{1} =-3 +\sqrt{14} \\\\x_{2} =-3 -\sqrt{14}

5 0
3 years ago
Read 2 more answers
How can you tell that a fraction is a unit fraction
a_sh-v [17]
You can tell that a fraction is a unit fraction when it is over a unit of one. This is also known as unit rate.
6 0
3 years ago
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Steffie makes a scale drawing for a crate with the demensions 15 inches long by 12 inches wide. Her scale factor is 1:3. Brian m
rodikova [14]

Answer:

Dimensions → (5 inches × 4 inches)

Step-by-step explanation:

Scale factor used for the drawing by Steffie = \frac{1}{3}

Since, scale factor = \frac{\text{Dimension of the drawing}}{\text{Actual dimension}}

For Steffie,

Actual length of the crate = \frac{\text{Dimension of the drawing}}{\text{Scale factor}}

                                           = \frac{15}{\frac{1}{3}}

                                           = 45 inches

Actual width of the crate = \frac{12}{\frac{1}{3} }

                                         = 36 inches

Since Brian used the scale factor = \frac{1}{9}

Length of the drawing = Actual length × Scale factor

                                     = 45 × \frac{1}{9}

                                    = 5 inches

Width of the drawing = Actual width × Scale factor

                                   = 36 × \frac{1}{9}

                                   = 4 inches

Therefore, dimensions of the drawing made by Brian are (5 inches × 4 inches)

6 0
3 years ago
A pair of linear equations is shown below:
trapecia [35]
That would be option D

The y intercepts are 1 and 4 and the slope are -1 and 2.
5 0
3 years ago
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