Answer:
here down is the answer
(2y/5y)^3+4y^2+6y
8y^3/125y^3 +16y^2+6y
8/125+16y^2+6y
8/125+16y^2+6y=0
16y^2+6y+8/125=0
it is in the form of quadratic equation
formula :
x=(-b+-square root of b^2-4ac) /2a
here a=16,b=6&c=8/125
x=(-b+-square root of b^2-4ac)/2a
x=(-6+-square root of 36-4.09)/2a here 4.09 came by calculation
x=(-6+-31.91)/2
so
x=(-6+31.91)/2 first (+);
x=25.91/2
x=12.955;
x=(-6-31.91)/2 then(-);
x=-37.91/2
x=-18.955 ;
ans is = 12.955&-18.955;
Always
a=b
subtract c from each side
a-c = b-c
I don't actually know, im not smart, I'm just answering for the points
Answer:
C
Step-by-step explanation:
If x is the average (arithmetic mean) of m and 9, y is the average of 2m and 15, and z is the average of 3m and 18,
x=(m+9)/2
y=(2m+15)/2
z=(3m+18)/2
the average of x, y, and z
=(x+y+z)/3
=(m+9+2m+15+3m+18)/3
=(6m+42)/3
=2m+14
ans is C
Answer:
idk why u asked this qn twice bt hope it will help u
