Answer:
quadrant 1 - (2,4)
quadrant 2 - (-3,4)
quadrant 3 - (-1, -5)
quadrant 4 - (6, -1)
Step-by-step explanation:
quadrant one consists of both x and y being positive.
quadrant two being the x is negative but the y is negative.
quadrant 3 has its x and y both negative.
finally, quadrant 4 has its x positive, but y is negative.
To calculate the area of a triangle you need the base & the altitude to this base:
Area triangle = 1/2(B x H)
Let's draw the altitude A intersecting BC in H. WE get now a right triangle AHB. We know AG = 9.2 we know the angle B =27°, so we can find the altitude AH through trigonometry :
sin(B) = opposite side over hypotenuse
sin(27°) = AH/AB==> sin(27°) =0.454 ==0.454= AH/9.2==>AH =0.454*9.2
AH = 4.177
Area triangle ABC = (1/2) * 11.9 * 4.177= 24.85
Answer:
a = 80
b = 3/4
the general equation is;
y = 80•(3/4)^x
Step-by-step explanation:
Here, we want to get the values of a and b
We are going to use the two points given
(0,80) and (1,60)
So we have this as;
for the first point;
80 = a•b^0
anything raised to power of 0 is 1
Thus;
80 = a * 1
a = 80
for the second point;
60 = 80 * b^1
60 = 80b
b = 60/80
b = 3/4
So we have the general equation as;
y = 80•(3/4)^x
since it travel at a constant speed. Calculate first its
speed of descent.
S = -3/4 mile / 1 ½ hr
S = -0.5 mile an hour
So the position of the diving bell relative to sea level 1
hour after it began its descent is
D = (0.5 mile/ hr) x 1 hr = - 0.5 mile
