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3 years ago

Find the equation of a line that passes through (2,-3), and that is parallel to 5x + y = -2.

Mathematics

1 answer:

Mashutka [201]3 years ago

3 0

Answer:

O y = -5x + 7

Step-by-step explanation:

$5x + y = -2 \\y = -5x - 2$

the slope of this line is -5 so the slope of a parallel line will also have to be -5

put it in point slope form:

y - - 3 = -5(x - 2)

y + 3 = -5x + 10

y = -5x + 7

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Kellie is playing with a toy building block that has the shape of a rectangular prism. What is the volume of the toy building bl

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The picture in the attached figure

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4 years ago

The step function f(x) is graphed. On a coordinate plane, a step graph has horizontal segments that are each 2 units long. The l

Sophie [7]

Answer:

b. -1

Step-by-step explanation:

(-3,-3) to (-1,-3)

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3 years ago

Read 2 more answers

Given the equation 3x + 25 = 7x - 5, which order of operations completely solves for x?

Minchanka [31]

Answer:

3x +25-25 = 7x -5 -25

3x = 7x -30

3x +7x = 7x +7x -30

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3 years ago

The circumference of a sphere was measured to be 90 cm with a possible error of 0.5 cm.

Akimi4 [234]

Answer:

Error in the sphere's surface: 29 $cm^2$ and relative error in surface measure: 0.011

Error in the sphere's volume: 205 $cm^3$ and relative error in the volume measure: 0.017

Step-by-step explanation:

(a)

The measured length (l) of the circumference is 90 cm with an error of 0.5 cm, that is:

$l=2\,\pi\,R=90\,cm\\R=\frac{90}{2\,\pi} \,cm=\frac{45}{\pi} \,cm=14.3239\,\,cm$

and with regards to the error:

$dl=0.5 \, cm\\dl=2\,\pi\,dR\\dR=\frac{dl}{2\,\pi} =\frac{1}{4\,\pi} cm = 0.0796\,cm$

then when we use the formula for the sphere's surface, we get:

$S=4\,\pi\,R^2\\dS=4\,\pi\,2\,R\,(dR)\\dS=8\,\,\pi\.(\frac{45}{\pi} \,\,cm)\,(\frac{1}{4\pi}\,cm) =\frac{90}{\pi} \,\,cm^2\approx \,29\,cm^2$

Then the relative error in the surface is:

$\frac{dS}{S} =\frac{90/\pi}{4\,\pi\,R^2} =\frac{1}{90} =0.011$

(b)

Use the formula for the volume of the sphere:

$V=\frac{4\,\pi}{3} R^3\\dV=\frac{4\,\pi}{3}\,3\,R^2\,(dR)=4\,\pi\,R^2\,(\frac{1}{4\pi}) \,cm=(\frac{45}{\pi})^2 \,\,cm^3\approx 205\,\,cm^3$

Then the relative error in the volume is:

$\frac{dV}{V} =\frac{205}{12310.5} \approx 0.017$

3 0

3 years ago