PLEASE HELP!!! Needed ASAP!
1 answer:
Answer:
6x - 3 y = 6
6x + 8y = -16
multiply equation 2 by -1
-6y -8y = 16
6x - 3y = 6
-11y =22
y = -2
substitute the value of y in 1
6x - 3(-2) = 6
6x + 6 =6
6x =0
x = 0
(x;y)
[0; -2]
9) 4x + 3y = 19
6x + 3y =33
multiply equation 2 by -1
4x + 3y = 19
-6x - 3y = -33
eliminate one variable by adding the equations
-2x =-14
x = 7
substitute the value of x in the equation
4(7) +3y = 19
28+ 3y = 19
3y =-9
y = -3
(x;y)
[7 ; -3]
10 ) 2x + 6y = 17
2x - 10y = 9
multiply by -1 in equation2
2x +6y = 17
-2x + 10 y = -9
eliminate one variable by adding the equations
16 y = 8
y = 1/2
substitute the value of y in the equation.
2x +6 (1/2) = 17
2x + 3 = 17
2x = 14
x = 7
x:y
[7 ; 1/2 ]
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Answer:
$5768.1
Step-by-step explanation:
Given data
Cost price= $13,000
Depreciation= 15%
Time= 5 years
The expression for the depreciation is given below
A= P(1-r)^t
Substitute
A=13000(1-0.15)^5
A=13000(0.85)^5
A=13000*0.4437
A=$5768.1
Hence after 5 years, the car will be $5768.1
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Answer:
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