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hram777 [196]
2 years ago
10

PLEASE HELP EASY 6TH GRADE MATH (pic is the possible answers) select the equation that represents the problem. let x represent t

he unknown. ms harris divided the 32 students in her class into groups. there are 8 students in each group. how many groups are there?

Mathematics
2 answers:
liubo4ka [24]2 years ago
6 0

Answer:

a

Step-by-step explanation:

Varvara68 [4.7K]2 years ago
5 0

Answer:  A  

Step-by-step explanation: this is too easy  

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Please help on this math question. <br><br>Will be marked as BRAINLEST!
leonid [27]

Answer:

20

Step-by-step explanation:

25 \times 25 - 15 \times 15 = 400

\sqrt{400}  = 20

6 0
2 years ago
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Can u pls help me with this question ​
Svet_ta [14]

Answer:

I think is 2/9 but I may be wrong

8 0
3 years ago
Consider the equation below. (If you need to use -[infinity] or [infinity], enter -INFINITY or INFINITY.)f(x) = 2x3 + 3x2 − 180x
soldier1979 [14.2K]

Answer:

(a) The function is increasing \left(-\infty, -6\right) \cup \left(5, \infty\right) and decreasing \left(-6, 5\right)

(b) The local minimum is x = 5 and the maximum is x = -6

(c) The inflection point is x = -\frac{1}{2}

(d) The function is concave upward on \left(- \frac{1}{2}, \infty\right) and concave downward on \left(-\infty, - \frac{1}{2}\right)

Step-by-step explanation:

(a) To find the intervals where f(x) = 2x^3 + 3x^2 -180x is increasing or decreasing you must:

1. Differentiate the function

\frac{d}{dx}f(x) =\frac{d}{dx}(2x^3 + 3x^2 -180x) \\\\\mathrm{Apply\:the\:Sum/Difference\:Rule}:\quad \left(f\pm g\right)'=f\:'\pm g'\\\\f'(x)=\frac{d}{dx}\left(2x^3\right)+\frac{d}{dx}\left(3x^2\right)-\frac{d}{dx}\left(180x\right)\\\\f'(x) =6x^2+6x-180

2. Now we want to find the intervals where f'(x) is positive or negative. This is done using critical points, which are the points where f'(x) is either 0 or undefined.

f'(x) =6x^2+6x-180 =0\\\\6x^2+6x-180 = 6\left(x-5\right)\left(x+6\right)=0\\\\x=5,\:x=-6

These points divide the number line into three intervals:

(-\infty,-6), (-6,5), and (5, \infty)

Evaluate f'(x) at each interval to see if it's positive or negative on that interval.

\left\begin{array}{cccc}Interval&x-value&f'(x)&Verdict\\(-\infty,-6)&-7&72&Increasing\\(-6,5)&0&-180&Decreasing\\(5, \infty)&6&72&Increasing\end{array}\right

Therefore f(x) is increasing \left(-\infty, -6\right) \cup \left(5, \infty\right) and decreasing \left(-6, 5\right)

(b) Now that we know the intervals where f(x) increases or decreases, we can find its extremum points. An extremum point would be a point where f(x) is defined and f'(x) changes signs.

We know that:

  • f(x) increases before x = -6, decreases after it, and is defined at x = -6. So f(x) has a relative maximum point at x = -6.
  • f(x) decreases before x = 5, increases after it, and is defined at x = 5. So f(x) has a relative minimum point at x = 5.

(c)-(d) An Inflection Point is where a curve changes from Concave upward to Concave downward (or vice versa).

Concave upward is when the slope increases and concave downward is when the slope decreases.

To find the inflection points of f(x), we need to use the f''(x)

f''(x)=\frac{d}{dx}\left(6x^2+6x-180\right)\\\\\mathrm{Apply\:the\:Sum/Difference\:Rule}:\quad \left(f\pm g\right)'=f\:'\pm g'\\\\f''(x)=\frac{d}{dx}\left(6x^2\right)+\frac{d}{dx}\left(6x\right)-\frac{d}{dx}\left(180\right)\\\\f''(x) =12x+6

We set f''(x) = 0

f''(x) =12x+6 =0\\\\x=-\frac{1}{2}

Analyzing concavity, we get

\left\begin{array}{cccc}Interval&x-value&f''(x)\\(-\infty,-1/2)&-2&-18\\(-1/2,\infty)&0&6\\\end{array}\right

The function is concave upward on (-1/2,\infty) because the f''(x) > 0 and concave downward on (-\infty,-1/2) because the f''(x) < 0.

f(x) is concave down before x = -\frac{1}{2}, concave up after it. So f(x) has an inflection point at x = -\frac{1}{2}.

7 0
3 years ago
In order to solve the following system of equations by addition, which of the following could you do before adding the equations
alexandr402 [8]
To solve the question, the both equations should have a positive value and a negative value with same number. Then one variable can be eliminated.

To eliminate X term first, we should multiply the first equation by 2 and second one by 3.
Then,
     6X - 12Y = -30
     -6X + 15Y = 70

Or

To eliminate Y term first, we should multiply the first equation by 5 and second one by 6.
 Then,
     15X - 30Y = -75
      -12X + 30Y = 84

According to the choices given 'A' is the correct answer.

5 0
3 years ago
Riley finds a recipe for bubble solution that uses 1 cup water, 1/4 cup dish soap,
pochemuha
8 cups of water because 1/4 of dish soap 1 cup of water so 2 cups of dish soap is 8 1/4’s which mean 8 cups of that make sense
6 0
2 years ago
Read 2 more answers
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