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3 years ago

Solve y - 5 =6 Plz solve it

Mathematics

2 answers:

creativ13 [48]3 years ago

6 0

Answer:

y = 11

Step-by-step explanation:

11-5=6

hope this helps

ira [324]3 years ago

3 0

Answer:

y = 11

Step-by-step explanation:

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What is the rate of change of a line that passes through the points (-3,5) and (2,-1)?

lara [203]

Answer:

3/4

Step-by-step explanation:

The slope of the line is

m = (y2-y1)/(x2-x1)

= (-2--5)/(6-2)

= (-2+5)/(6-2)

=3/4

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3 years ago

Figure ABCD is rotated clockwise about the origin through 90°. Identify the coordinates for the given figure after 90° rotation

nydimaria [60]

Answer:

D[3, 3], C[1, 4], B[0, 1], A[4, -1]

Step-by-step explanation:

Whenever you are doing a 90° clockwise rotation ABOUT THE ORIGIN, it is in the form of [y, -x], meaning you take the y and make it your x, then take your original x and put its OPPOSITE.

90° counterclockwise rotation → [-y, x]

90° clockwise rotation → [y, -x]

I hope this helps, and as always, I am joyous to assist anyone at any time.

8 0

3 years ago

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Question 14

MissTica

Answer:

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7 0

2 years ago

How can csc^2-cot^2 = 1?

Softa [21]

ANSWER

By simplifying the left hand side using the Pythagorean Identity.

EXPLANATION

The given identity is

$\csc^{2} (x) - \cot^{2} (x) = 1$

Take the left hand side and simplify to get the right hand side.

$\csc^{2} (x) - \cot^{2} (x) = \frac{1}{\sin^{2} (x)} - \frac{ \cos^{2} (x)}{\sin^{2} (x)}$

Collect LCM for the denominators.

$\csc^{2} (x) - \cot^{2} (x) = \frac{1 - \cos^{2} (x)}{\sin^{2} (x)}$

Recall the Pythagorean Identity.

$\cos^{2} (x) + \sin^{2} (x) = 1$

This implies that:

$1 - \cos^{2} (x) = \sin^{2} (x)$

We substitute this to get,

$\csc^{2} (x) - \cot^{2} (x) = \frac{\sin^{2} (x)}{\sin^{2} (x)}$

$\csc^{2} (x) - \cot^{2} (x) = 1$

6 0

3 years ago

Help me pleaseee (10 points )

Gemiola [76]

Answer:

m<T = , m<M = and m<Z =

Step-by-step explanation:

From the given ∆TMZ, let the measure angle T be represented by T.

So that,

m<M = 2T + 6°

m<Z = 5T - 50°

Sum of angles in a triangle =

T + (2T + 6°) + (5T - 50°) =

8T - =

8T = +

T =

Therefore,

i. m<T =

ii. m<M = 2T + 6°

= 2 x + 6°

m<M =

iii. m<Z = 5T - 50°

= 5 x - 50°

= - 50°

m<Z =

5 0

3 years ago