Answer:
30 m/s
Step-by-step explanation:
Let's say the distance from the first car to the intersection is x, and the distance from the second car to the intersection is y.
The distance between the cars can be found with Pythagorean theorem:
d² = x² + y²
Taking derivative with respect to time:
2d dd/dt = 2x dx/dt + 2y dy/dt
d dd/dt = x dx/dt + y dy/dt
We know that x = 200, dx/dt = -25, y = 150, and dy/dt = -50/3.
To find dd/dt, we still need to find d.
d² = x² + y²
d² = (200)² + (150)²
d = 250
Plugging everything in:
250 dd/dt = (200) (-25) + (150) (-50/3)
dd/dt = -30
The cars are approaching each other at a rate of 30 m/s at that instant.
Answer:
second option is correct onee
Step-by-step explanation:
mark me brainliest
Answer:
x=2
Step-by-step explanation:
Here what we need is that the ratios be equal, which is:
x:(5/2) = 8:10 or, what is the same:
x/(5/2) = 8/10
Lets pick the left term x/(5/2) and multiply both numerator and denominator by 2 to eliminate the fraction on the denominator:
2x/2(5/2) = 2x/5
Now, we would like to make a 10 appear on the denominator. As we already have a five we need to multiply numerator and denominator by the num that, multiplied by 5 gives as 10, this is 2:
2(2x)/2(5) = 4x / 10
So, we transformed x/(5/2) in 4x/10, and both are the same, so we can replace it on our first equation:
4x/10 = 8/10
As both denominators are equal, we can concentrate only in numerators:
4x = 8
Dividing both sides by 4:
x = 2
So, for x=2 both ratios are equivalents.
A mixed number is an addition of its whole and fractional parts.
2
+
1
3
Add
2
and
1
3
.
Tap for more steps...
7
3
The result can be shown in multiple forms.
Exact Form:
7
3
Decimal Form:
2.
¯
3
Mixed Number Form:
2
1
3
