For each question, identify the population and a possible sample.

Find the volume of the sphere. Either enter an exact answer in terms of \piπpi or use 3.143.143, point, 14 for \piπpi and round

olga55 [171]

Answer:

3053.63

Step-by-step explanation:

Use the equation for sphere volume: $V=\frac{4}{3}\pi r^3$

Plug the values in and get $V=\frac{4}{3}\pi 9^3=3053.62805929$

≈ 3053.63

Note: exact value of pi used.

8 0

3 years ago

Read 2 more answers

I need to equation for the radius of a 400m running track I know the answer is 36.5 and I know the formula is =2<img src="https:

miskamm [114]

This formula only applies if the track is circular. If it is, then we write the equation:

2*r*pi=400

Dividing by 2pi, we see that:

r=200/pi

This is approximately 63.66.

6 0

3 years ago

A yogurt shop offers 5 different flavors and11 different topping how many choices are possible for a single serving of yogurt wi

GalinKa [24]

If you have 5 flavors and 11 toppings, but you can only have 1 of each you take 5×11 to get 55

3 0

3 years ago

A sample of 1200 computer chips revealed that 45% of the chips fail in the first 1000 hours of their use. The company's promotio

yaroslaw [1]

Answer:

$z=\frac{0.45 -0.48}{\sqrt{\frac{0.48(1-0.48)}{1200}}}=-2.08$

$p_v = P(Z$

So the p value obtained was a low value and using the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of chips that fail in the first 1000 hours of their use is not significantly less than 0.48.

Step-by-step explanation:

Data given and notation

n=1200 represent the random sample taken

$\hat p=0.45$ estimated proportion of chips that fail in the first 1000 hours of their use

$\mu_0 =0.48$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportion si less then 0.48:

Null hypothesis: $p\geq 0.48$

Alternative hypothesis: $p < 0.48$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion is significantly different from a hypothesized value .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.45 -0.48}{\sqrt{\frac{0.48(1-0.48)}{1200}}}=-2.08$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a left tailed test the p value would be:

$p_v = P(Z$

So the p value obtained was a low value and using the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of chips that fail in the first 1000 hours of their use is not significantly less than 0.48.

6 0

4 years ago

A picture has the ratio of 2/3 inch per 1/2 cm. What is the unit rate inches per centimeter?

Readme [11.4K]

Answer:

4/6

Step-by-step explanation:

x2

hope it helps

4 0

3 years ago