Find the slope of the line that contains (1,6) and (10, -9).

2 answers:

7 0

So,

To find the slope, simply subtract the given solutions and put them in the proper form.

10 - 1 = 9
-9 - 6 = -15

$Slope = \frac{-15}{9} \ or\ \frac{-5}{3} \ or\ -\frac{5}{3}$

My name is Ann [436]3 years ago

3 0

M= $\frac{y1-y2}{x1-x2}$ = $\frac{6-(-9)}{1-10}= \frac{15}{-9}=- \frac{5}{3}$

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Forces of 9 lbs and 13 lbs act at a 38º angle to each other. Find the magnitude of the resultant force and the angle that the re

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Answer: $R=20.84\ lb\quad 22.57^{\circ},15.43^{\circ}$

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$\Rightarrow R=\sqrt{9^2+13^2+2(9)(13)\cos 38^{\circ}}\\\Rightarrow R=\sqrt{81+169+184.394}\\\Rightarrow R=\sqrt{434.394}\\\Rightarrow R=20.84\ lb$

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$\Rightarrow \alpha=\tan^{-1}\left( \dfrac{b\sin \theta}{a+b\cos \theta}\right)\\\\\text{Considering 9 lb force along the x-axis}\\\\\Rightarrow \alpha =\tan^{-1}\left( \dfrac{13\sin 38^{\circ}}{9+13\cos 38^{\circ}}\right)\\\\\Rightarrow \alpha =\tan^{-1}(\dfrac{8}{19.244})\\\\\Rightarrow \alpha=22.57^{\circ}$