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3 years ago

The answer to the question in the picture

Mathematics

1 answer:

wolverine [178]3 years ago

7 0

Add them all up to get it

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Dogwood Park is 30 yards long by 20 yards wide. Kylie is making plans to double the area by adding a strip at one end and anothe

Alik [6]

We are asked to solve for the value of "x" such that when it is added in the original area of the park it will double the area. Let us compute first the area of the original dog park (A1) and the solution is shown below:
Area = Lenght*Width = L*W where L=30 yards and W=20 yards
Area = 30*20
Area = 600 yards squared
Solving for the x, when x is added to both sides which double the area:
A1*2 = (L + 2x)*W
600*2 = (30+2x)*20
1200 / 20 = 30+2x
60 = 30 + 2x
60-30 = 2x
30/2 =x
15 = x

The value of x is 15 yards.

8 0

3 years ago

Write the equation of a circle centered at the

Fudgin [204]

Answer:

$(x+4)^2+(y+6)^2=100$

Step-by-step explanation:

Given a circle centred at the point P(-4,-6) and passing through the point

R(2,2).

To find its equation, we follow these steps.

Step 1: Determine its radius, r using the distance formula

For point P(-4,-6) and R(2,2)

$\text{Distance Formula=}\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\\text{Radius=}\sqrt{(2-(-4))^2+(2-(-6))^2} \\=\sqrt{(2+4))^2+(2+6)^2}\\=\sqrt{6^2+8^2}\\=\sqrt{100}\\Radius=10$

Step 2: Determine the equation

The general form of the equation of a circle passing through point (h,k) with a radius of r is given as: $(x-h)^2+(y-k)^2=r^2$

Centre,(h,k)=P(-4,-6)

r=10

Therefore, the equation of the circle is:

$(x-(-4))^2+(y-(-6))^2=10^2\\\\(x+4)^2+(y+6)^2=100$

3 0

3 years ago

What times what equals 63

Temka [501]

7 time 3 or 8 times
2

4 0

3 years ago

Read 2 more answers

What is the product of 3a + 5 and 2a2 + 4a – 2?

Triss [41]

Answer:

6a^3+ 22a^4+ 14a-10

Step-by-step explanation:

6a^3 10a^2 12a^2 20a -6a -10

7 0

3 years ago

A finance magazine did a survey and found that the average American family spends $1,600 on a summer vacation. If the distributi

Andre45 [30]

Answer:

Step-by-step explanation:

Let X be the normal distribution

Kindly find attached a detailed annotation of the solution to the problem.

in the attached document, we found the value that corresponds to 80th percentile, hence we found the value such that the probability that the variable x is lower than this value is 0.8.

Also, from the calculation, we found that the value which corresponds to the 80th percentile is $1945

6 0

3 years ago